A horizontal camera boom is attached to a stand at a pivot. The boom has negligible weight. All the forces in the table act vertically downwards.
| force | side of pivot | perpendicular distance from the pivot |
|---|---|---|
| weight of camera, 48 N | right | 0.75 m |
| weight of counterweight, 90 N | left | 0.30 m |
| additional force, FFF | left | 0.20 m |
Calculate the size of force F F\,F needed to keep the boom in rotational equilibrium.
The additional force is instead 35 N. Explain which direction the boom starts to turn.
102 exam-style questions on Edexcel GCSE Physics 9.2 Moments, covering 9.2.1 Rotational effects of forces and moments, 9.2.2 The principle of moments, and 9.2.3 Levers and gears. Each one has a worked solution and a mark scheme showing where the marks go.