A person uses a bottle opener to remove a cap.
The opener turns about the point where it rests on the edge of the cap. This point is the pivot.
The person applies a force of 60 N at a point 0.15 m from the pivot. The force acts at right angles to the line joining this point to the pivot.
State the equation linking moment, force and distance normal to the direction of the force.
Calculate the moment of the force about the pivot.
The opener is moved so that the line of action of the force passes through the pivot.
State the moment of the force about the pivot in this position.
The moment calculated in part (b) is transmitted through the opener to the cap.
The opener applies a force to the cap at a perpendicular distance of 0.025 m from the pivot.
Calculate the force applied to the cap.
102 exam-style questions on Edexcel GCSE Physics 9.2 Moments, covering 9.2.1 Rotational effects of forces and moments, 9.2.2 The principle of moments, and 9.2.3 Levers and gears. Each one has a worked solution and a mark scheme showing where the marks go.