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9.2 Moments

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Question 2

Which of the following is the correct equation to calculate the moment of a force?

A

moment of a force=force×perpendicular distance from pivot\text{moment of a force} = \text{force} \times \text{perpendicular distance from pivot}moment of a force=force×perpendicular distance from pivot

B

moment of a force=force÷perpendicular distance from pivot\text{moment of a force} = \text{force} \div \text{perpendicular distance from pivot}moment of a force=force÷perpendicular distance from pivot

C

moment of a force=force×parallel distance from pivot\text{moment of a force} = \text{force} \times \text{parallel distance from pivot}moment of a force=force×parallel distance from pivot

D

moment of a force=force÷parallel distance from pivot\text{moment of a force} = \text{force} \div \text{parallel distance from pivot}moment of a force=force÷parallel distance from pivot

Markscheme

9.2 Moments Questions

  1. GCSE
  2. /Physics
  3. /9.2 Moments

9 exam-style questions on Edexcel GCSE Physics 9.2 Moments, covering 9.2.1 Rotational effects of forces and moments, 9.2.2 The principle of moments, and 9.2.3 Levers and gears. Each one has a worked solution and a mark scheme showing where the marks go.

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