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Inducing current, generators and microphones

Inducing current, generators and microphones

13.1.1 Producing an electric current by induction

Inducing a potential difference

Definition

Electromagnetic induction

Electromagnetic induction is the production of a potential difference across the ends of a conductor when the magnetic field through that conductor changes.

Definition

Generator effect

The generator effect is the induction of a potential difference in a conductor when there is relative movement between the conductor and a magnetic field.

Definition

Induced potential difference

An induced potential difference is the potential difference produced across the ends of a conductor by a changing magnetic field.

  1. A conductor has a potential difference induced across its ends whenever the magnetic field passing through that conductor changes.
  2. The change can be produced by relative movement between the conductor and a magnet, or by a magnetic field that grows or collapses in strength while everything stays still.
  3. A stationary conductor sitting in a steady magnetic field has nothing induced across it, however strong that field is, because nothing about the field through it is changing.
  4. The induced potential difference exists across the ends of the conductor whether or not any current flows, in the same way that a cell has a potential difference across its terminals before it is connected to anything.
  5. For a straight wire, the field through the wire only changes if the wire cuts across the magnetic field lines, so moving the wire along the field lines induces nothing.

When an induced current flows

Definition

Induced current

An induced current is the current driven by an induced potential difference when the conductor forms part of a complete circuit.

  1. An induced current flows only when the conductor forms part of a complete circuit.
  2. Connecting the ends of a coil to a sensitive ammeter completes the circuit, so the needle deflects while the magnet is moving and returns to zero when the movement stops.
  3. Leaving the ends of the coil unconnected still gives an induced potential difference, but no charge can circulate, so no current is measured.
  4. The size of the induced current follows I=VRI=\dfrac{V}{R}I=RV​, so a coil made of thicker wire or a circuit with less resistance gives a larger current for the same induced potential difference.
  5. The needle deflects in one direction while the magnet approaches and in the opposite direction while it recedes, which shows that the direction of the induced current depends on the direction of the change.

Ways of producing the change

  1. Pushing a bar magnet into a coil of wire increases the field through the coil, and pulling it out decreases the field, so both movements induce a potential difference.
  2. Holding the magnet still and moving the coil over it works exactly as well, because only the relative movement of the two matters.
  3. Moving a straight wire downwards between the poles of a horseshoe magnet makes the wire cut across the field lines and induces a potential difference along its length.
  4. Rotating a coil continuously inside a magnetic field keeps the field through the coil changing, which is how a generator produces a continuous output.
  5. Switching a current on or off in a nearby coil makes that coil's magnetic field grow or collapse, and the changing field induces a potential difference in the second coil even though nothing moves.
  6. Moving a magnet sideways past a coil, so that the field through the coil barely changes, induces very little.

Direction of the induced potential difference

  1. Reversing the direction of movement reverses the induced potential difference, so pushing a magnet in and pulling it out give deflections on opposite sides of zero.
  2. Reversing the poles of the magnet, so that the south pole leads instead of the north pole, also reverses the induced potential difference.
  3. Reversing the movement and the poles together leaves the direction of the induced potential difference unchanged, because the two reversals cancel.
  4. Moving the magnet in and out repeatedly produces a potential difference that repeatedly changes direction, which is an alternating potential difference.

Energy transfer during induction

  1. The induced current in the coil is itself a current in a loop of wire, so it produces its own magnetic field.
  2. This induced field always acts to oppose the change that produced it, so the coil repels an approaching pole and attracts a receding pole.
  3. A force must therefore be applied to keep the magnet moving, and the work done against that opposing force is the source of the electrical energy.
  4. Energy is transferred from the kinetic store of the moving magnet, through the electrical working of the circuit, and finally to the thermal store of the surroundings as the induced current heats the wires.
  5. If the induced field helped the change rather than opposing it, the magnet would accelerate on its own and energy would appear from nowhere, which conservation of energy forbids.
  6. This is why a bicycle dynamo makes the pedals harder to turn once its lamp is switched on, and why a generator supplying more current needs more driving power.
Practical

Investigating induction with a magnet and a coil

  • Aim: to show that a potential difference is induced only while the magnetic field through a coil is changing, and to find what controls its direction.
  • Apparatus: strong cylindrical bar magnet, coil of insulated copper wire of about 400 turns wound on a hollow tube, centre-reading galvanometer or a data logger with a voltage sensor, connecting leads, soft iron rod, retort stand and clamp, and a metre rule.
  • Variables: the movement of the magnet relative to the coil is the independent variable, the reading on the galvanometer is the dependent variable, and the same magnet, coil, circuit and starting distance are kept the same throughout.
  • Method, setting up:
    • Connect the two ends of the coil to the centre-reading galvanometer so that the coil and meter form a complete circuit.
    • Clamp the coil so its hollow axis is horizontal and check that the needle rests on zero with nothing moving.
    • Mark a starting position on the bench about 10 cm10\ \text{cm}10 cm from the mouth of the coil so that every run begins from the same place.
  • Method, showing that change is needed:
    • Hold the magnet motionless just inside the coil and record the reading, which stays at zero.
    • Push the north pole of the magnet steadily into the coil and record the direction and size of the deflection.
    • Hold the magnet still inside the coil and record the reading again, which returns to zero even though the magnet is inside.
    • Pull the magnet out at the same speed and record the direction of the deflection.
  • Method, testing direction:
    • Turn the magnet round so the south pole leads, repeat the push and the pull, and record the directions.
    • Keep the magnet still and move the coil towards and away from it instead, then record the deflections.
    • Slide the magnet sideways past the mouth of the coil rather than into it, and record how small the deflection becomes.
    • Repeat each run three times so that a direction is confirmed rather than read from one uncertain flick of the needle.
  • Measurements and processing: record for each run whether the needle moved left or right and roughly how far, then tabulate the direction of movement, the leading pole and the direction of deflection so the pattern can be read off.
  • Expected pattern: the reading is zero whenever nothing is moving, the deflection reverses when the movement reverses, the deflection reverses when the poles are swapped, and moving the coil instead of the magnet gives the same result as moving the magnet.
  • Feeling the opposition: push the magnet in quickly with the circuit complete, then disconnect one lead and repeat, and notice that the magnet is easier to push when no current can flow.
  • Sources of uncertainty: hand movements vary in speed between runs, the needle swings and settles slowly, the starting distance is hard to reproduce, and the magnet may not stay on the axis of the coil.
  • Improvements: replace the galvanometer with a data logger to capture the shape of each pulse, drop the magnet down a vertical tube through the coil so the speed is reproducible, and use a longer coil so the magnet stays on the axis.
  • Safety: keep the magnet away from phones, cards and computers, do not let a strong magnet snap onto the clamp and trap fingers, and support the stand so the clamped coil cannot topple.

Reading an induction trace

  1. A data logger connected across the coil records how the induced potential difference changes with time, giving a pulse rather than a steady value.
  2. Each pulse begins at zero, rises to a peak while the field is changing fastest, and returns to zero when the movement stops.
  3. A faster movement gives a pulse that is taller and narrower, because the same change in the field is squeezed into a shorter time.
  4. A pulse below the zero line means the induced potential difference is in the opposite direction to one above the line, not that it is smaller.
Example

A magnet falling through a coil

  • A magnet is released above a vertical tube so that it falls straight through a coil connected to a data logger.
  • As the magnet approaches and enters the coil, the field through the coil increases, and the trace rises to a peak on one side of zero.
  • As the magnet leaves the coil, the field through the coil decreases, so the trace swings to a peak on the other side of zero.
  • The second peak is taller and narrower than the first, because gravity has accelerated the magnet and the field changes more quickly on the way out.
  • The trace passes through zero at the instant the magnet is level with the centre of the coil, where the field through the coil is momentarily not changing.
  • The magnet reaches the bench slightly more slowly than an identical unmagnetised bar, because the induced current opposes its motion and some of its energy is transferred electrically.
Exam technique

Explaining an induced potential difference

  • Name the change first, such as the magnet moving into the coil, then state that the magnetic field through the coil changes, then state that a potential difference is induced.
  • Say potential difference is induced, and add that a current flows only if the circuit is complete.
  • When asked why the reading is zero, say that the magnetic field through the coil is not changing rather than saying there is no field.
  • For a direction question, state which single thing has been reversed, the movement or the poles, and conclude that the induced current reverses.
  • For an energy question, name the store the energy comes from, the kinetic store of whatever is being moved, and say that work is done against the opposing force.
Common Mistake
  • Do not write that a magnet held still inside a coil induces a potential difference, because the field through the coil is steady.
  • Do not say that the magnet creates a current in the wire directly, because the magnetic field induces a potential difference and the circuit then carries a current.
  • Do not claim that a stronger magnet always gives a reading, since a strong magnet at rest gives nothing at all.
  • Do not confuse this with the motor effect, where a current placed in a field produces a force rather than movement producing a potential difference.
  • Do not describe the induced magnetic field as helping the movement, because that would break conservation of energy.
Self review
  • State what must happen to the magnetic field through a coil for a potential difference to be induced across it.
  • Explain why a galvanometer connected to a coil reads zero while a magnet rests inside the coil.
  • Describe two separate changes that each reverse the direction of an induced current.
  • Explain why work must be done to keep a magnet moving into a coil that is part of a complete circuit.
  • Describe how the trace from a data logger changes when a magnet is moved into a coil more quickly.

13.1.2 Factors affecting the induced potential difference

Rate of change of the magnetic field

Definition

Induced potential difference

An induced potential difference is the potential difference produced across the ends of a conductor by a changing magnetic field.

Definition

Induced current

An induced current is the current driven by an induced potential difference when the conductor forms part of a complete circuit.

  1. The size of the induced potential difference is set by the rate at which the magnetic field through the conductor changes, not by the size of the field itself.
  2. A change completed in a shorter time gives a larger induced potential difference, and the same change spread over a longer time gives a smaller one.
  3. Anything that makes the field through the coil change by a larger amount, or change in a shorter time, increases the induced potential difference.
  4. The induced current grows in proportion to the induced potential difference for a fixed circuit resistance, so the same list of factors controls the current reading.
  5. Each factor works by changing either how much the field through the coil changes or how quickly that change happens.

The five controlling factors

  1. Speed of relative movement:
    1. Moving the magnet or the coil faster completes the same change in the field in less time, so the rate of change is greater.
    2. Doubling the speed roughly doubles the peak induced potential difference for the same magnet and coil.
  2. Number of turns on the coil:
    1. Each turn of wire has a potential difference induced across it, and the turns are joined in series, so their contributions add together.
    2. A coil of 200200200 turns gives about twice the induced potential difference of an otherwise identical coil of 100100100 turns.
  3. Strength of the magnetic field:
    1. A stronger magnet, or two magnets used together, produces a larger change in the field for the same movement.
    2. Slotting a soft iron core into the coil concentrates the field lines through the coil and increases the induced potential difference sharply.
  4. Area of the coil:
    1. A coil of larger cross-sectional area has more of the magnetic field passing through it, so the same movement changes the field through it by more.
  5. Orientation of the movement:
    1. Moving a wire at right angles to the field lines makes it cut through the greatest number of them and gives the largest induced potential difference.
    2. Moving a wire along the field lines makes it cut none of them, so nothing is induced.

Factors that make no difference

  1. The resistance of the external circuit changes the induced current but not the induced potential difference.
  2. The material of the wire changes the resistance of the coil, so it affects the current rather than the induced potential difference.
  3. The length of time for which the magnet is left inside the coil makes no difference once it has stopped moving, because the reading has already fallen to zero.
  4. The absolute position of the magnet matters only through how much the field through the coil changes as it moves.
Practical

Investigating what changes the induced potential difference

  • Aim: to find how the peak induced potential difference depends on the speed of movement, the number of turns on the coil and the strength of the magnetic field.
  • Apparatus: two or three coils of known turns such as 100100100, 200200200 and 400400400 turns, identical bar magnets, a vertical plastic tube of about 1 m1\ \text{m}1 m, a data logger with a voltage sensor set to record at a high sampling rate, soft iron core, retort stand and clamp, metre rule, foam landing pad and connecting leads.
  • Variables, speed investigation: the drop height above the coil is the independent variable, the peak induced potential difference is the dependent variable, and the same magnet, coil, number of turns and sampling rate are controlled.
  • Variables, turns investigation: the number of turns on the coil is the independent variable, the peak induced potential difference is the dependent variable, and the drop height, magnet and coil diameter are controlled.
  • Method, setting up:
    • Clamp the plastic tube vertically and slide the coil onto it so that the magnet must fall straight through the middle of the coil.
    • Connect the coil to the voltage sensor and set the data logger to record for a short interval at a high sampling rate so the pulse shape is captured.
    • Place a foam pad at the bottom of the tube so the magnet is not damaged when it lands.
    • Use the metre rule to mark release heights on the tube, measured from the top of the coil.
  • Method, changing the speed:
    • Release the magnet from the lowest marked height without pushing it, and record the peak induced potential difference from the trace.
    • Repeat the drop three times from that height and calculate a mean peak value.
    • Repeat for at least five increasing release heights, which give increasing speeds at the coil.
    • Calculate the speed at the coil for each height using v=2ghv=\sqrt{2gh}v=2gh​ so that speed can be plotted rather than height.
  • Method, changing the number of turns:
    • Fix one release height and use it for every coil so the speed at the coil is the same each time.
    • Swap the coil for one with a different number of turns, keeping the coil diameter and the magnet the same.
    • Take three drops with each coil and record the mean peak induced potential difference.
  • Method, changing the field strength:
    • Repeat one fixed drop with a single magnet, then with two identical magnets held with like poles together to give a stronger field.
    • Repeat the fixed drop with a soft iron core inserted into the coil and compare the peak value with the empty coil.
  • Measurements and processing: tabulate release height, calculated speed, number of turns and the three peak readings with their mean, then plot peak induced potential difference against speed and against number of turns.
  • Expected pattern: both graphs are straight lines through the origin, the stronger field gives a larger peak at the same speed, and the soft iron core gives the largest increase of all.
  • Sources of uncertainty: the magnet may tilt or rub inside the tube, the data logger may miss the true peak if the sampling rate is too low, the coil may shift on the tube between runs, and the magnet may lose speed to air resistance.
  • Improvements: use light gates to measure the actual speed at the coil rather than calculating it, raise the sampling rate until the peak value stops changing, and secure the coil to the tube so it cannot move.
  • Safety: clamp the tube so it cannot fall, keep magnets away from cards and phones, and stand clear of the base of the tube while a magnet is falling.

Reading the graphs and traces

  1. A straight line through the origin on a graph of peak induced potential difference against speed shows that the two quantities are directly proportional.
  2. A straight line through the origin on a graph of peak induced potential difference against number of turns shows the same proportional relationship for the turns.
  3. Doubling the speed makes the pulse on an oscilloscope twice as tall and half as wide, because the same overall change in the field happens in half the time.
  4. The area under a pulse of induced potential difference against time barely changes when only the speed changes, since the total change in the field is the same.
  5. Reading a value off a straight line through the origin is a matter of scaling, so a coil of triple the turns at double the speed gives six times the original peak.
Example

Predicting a peak induced potential difference

  • A magnet dropped from a fixed height through a 150150150 turn coil gives a peak induced potential difference of 0.30 V0.30\ \text{V}0.30 V.
  • The coil is replaced by an identical coil of 450450450 turns, and the drop height is raised so that the magnet passes the coil at twice the speed.
  • Tripling the number of turns multiplies the peak value by 333, because each turn contributes an equal share.
  • Doubling the speed multiplies the peak value by a further 222, because the field changes in half the time.
  • The predicted peak is V=0.30×3×2=1.8 VV=0.30\times3\times2=1.8\ \text{V}V=0.30×3×2=1.8 V.
  • Dropping the same magnet from the original height through the 450450450 turn coil would give 0.30×3=0.90 V0.30\times3=0.90\ \text{V}0.30×3=0.90 V, which separates the effect of the turns from the effect of the speed.
Exam technique

Answering a factors question

  • Name the factor you are changing, state whether it is increased or decreased, then link it to the rate at which the magnetic field through the coil changes.
  • Finish with the effect on the induced potential difference, since a factor named without an effect earns nothing.
  • For a comparison of two traces, quote both the height of the peak and the width of the pulse rather than only the height.
  • Say directly proportional only when the graph is a straight line passing through the origin.
  • When asked for one change that increases the reading, choose a factor you can justify in a single step, such as adding more turns, rather than a vague answer such as improving the equipment.
Common Mistake
  • Do not write that a stronger magnet held still gives a larger induced potential difference, because a steady field induces nothing.
  • Do not confuse the number of turns with the length of wire in a straight conductor, since only turns linking the changing field add up.
  • Do not give the resistance of the circuit as a factor affecting the induced potential difference, because it affects only the induced current.
  • Do not describe a pulse below the zero line as a smaller induced potential difference, since it is the same size in the opposite direction.
  • Do not change the drop height and the coil in the same run, because the effect of each factor then cannot be separated.
Self review
  • State the quantity that determines the size of an induced potential difference.
  • List four changes that each increase the peak induced potential difference in a coil and magnet arrangement.
  • Explain why a coil of 400400400 turns gives twice the reading of an identical coil of 200200200 turns.
  • Describe how a pulse on an oscilloscope changes when the magnet passes the coil twice as fast.
  • Explain why inserting a soft iron core into the coil raises the induced potential difference.

13.1.3 Alternators and dynamos

Generating with a rotating coil

Definition

Alternator

An alternator is a generator in which a coil rotates in a magnetic field and connects to the external circuit through slip rings, so it produces an alternating potential difference.

Definition

Dynamo

A dynamo is a generator in which a coil rotates in a magnetic field and connects to the external circuit through a split-ring commutator, so it produces a direct potential difference.

  1. A generator turns a coil of wire inside a magnetic field so that the field through the coil changes continuously and a potential difference is induced without pause.
  2. As the coil rotates, the two long sides of the coil sweep through the field lines, and the rate at which they cut the field lines varies smoothly through each turn.
  3. When the plane of the coil lies parallel to the field lines, the sides are moving straight across the field lines, so they cut them fastest and the induced potential difference is at its peak.
  4. When the plane of the coil lies at right angles to the field lines, the sides are moving momentarily along the field lines, so they cut none of them and the induced potential difference is zero.
  5. The coil is driven by an external source of energy, such as a steam turbine in a power station, a bicycle wheel or a hand crank, and energy is transferred from the kinetic store of the rotating coil to the electrical circuit.
  6. Both types of generator can be built the other way round, with the magnet rotating inside a fixed coil, because only the relative movement matters.

The alternator and slip rings

Definition

Alternating current

Alternating current is a current that repeatedly reverses its direction of flow.

  1. An alternator connects each end of the rotating coil to its own slip ring, and each slip ring is pressed against a fixed carbon brush.
  2. Each end of the coil therefore stays connected to the same brush and the same side of the external circuit for the whole rotation.
  3. Every half turn the two sides of the coil swap places in the field, so the induced potential difference reverses direction, and the external circuit sees that reversal.
  4. The output over one rotation rises from zero to a positive peak, falls back through zero, reaches an equal negative peak and returns to zero, tracing a smooth curve.
  5. One complete rotation of the coil gives one complete cycle of the output, so the frequency of the output equals the number of rotations each second.
  6. The alternators in UK power stations turn at a rate that gives mains electricity a frequency of 50 Hz50\ \text{Hz}50 Hz, so the output completes 505050 cycles every second.

The dynamo and the commutator

Definition

Direct current

Direct current is a current that flows in one direction only.

  1. A dynamo connects the coil to a split-ring commutator, which is a single ring cut into two halves that each press against one of the fixed brushes.
  2. At the moment when the induced potential difference in the coil would reverse, the two halves of the commutator swap brushes.
  3. The connections to the external circuit reverse at the same instant as the potential difference in the coil reverses, so the two reversals cancel and the output keeps one direction.
  4. The output over one rotation is two positive humps, each rising from zero to a peak and falling back to zero, because the negative half of each cycle has been flipped over.
  5. The output is direct because it never crosses the zero line, even though its size changes constantly, so it is described as a pulsing direct potential difference.
  6. The commutator is the only difference in principle between the two machines, so an alternator becomes a dynamo when its slip rings are replaced by a split ring.

Changing the output of a generator

  1. Turning the coil faster raises the peak potential difference, because the coil sides cut the field lines more quickly.
  2. Turning the coil faster also raises the frequency, because each rotation takes less time, so the peaks on a trace move closer together.
  3. Adding more turns to the coil, using stronger magnets or using a coil of larger area raises the peak potential difference while leaving the frequency unchanged.
  4. Placing the coil on a soft iron armature concentrates the field lines through the coil and raises the peak value further.
  5. Drawing more current from a generator makes it harder to turn, because the induced current in the coil produces a field that opposes the rotation.
Practical

Investigating a model generator

  • Aim: to compare the output of an alternator and a dynamo and to find how the output depends on the rate of rotation.
  • Apparatus: demountable model generator fitted with interchangeable slip rings and a split-ring commutator, strong horseshoe magnet or a pair of magnadur magnets on a yoke, coil wound on a soft iron armature, hand crank or a small motor with a variable supply to drive it, oscilloscope or data logger with a voltage sensor, low-voltage lamp, tachometer or a stroboscope, and connecting leads.
  • Variables: the rate of rotation of the coil is the independent variable, the peak induced potential difference and the frequency of the output are the dependent variables, and the coil, magnets, armature and circuit are controlled.
  • Method, setting up:
    • Mount the coil on the armature between the poles of the magnet so that it turns freely without touching them.
    • Fit the slip rings first, check that both brushes press lightly on their rings, and connect the brushes to the oscilloscope.
    • Set the oscilloscope timebase so that two or three complete cycles fill the screen, and note the volts per division and the time per division.
  • Method, comparing the two outputs:
    • Turn the crank at a steady rate and sketch the trace, noting whether it crosses the zero line.
    • Stop, replace the slip rings with the split-ring commutator without disturbing the coil or magnets, and repeat at the same rate of rotation.
    • Sketch the second trace alongside the first and mark the zero line on both so the two can be compared directly.
  • Method, changing the rate of rotation:
    • Refit the slip rings and drive the coil with the small motor so the rate of rotation can be set repeatably.
    • Measure the rate of rotation with the tachometer, then read the peak height and the period of one cycle from the trace.
    • Repeat for at least five rates of rotation, taking three readings at each rate and calculating means.
    • Connect the lamp in place of the oscilloscope and observe that it lights more brightly as the rate of rotation increases.
  • Measurements and processing: read the peak potential difference as the greatest height of the trace above the zero line, read the period TTT as the time for one complete cycle, calculate the frequency from f=1Tf=\dfrac{1}{T}f=T1​, and plot peak potential difference against rate of rotation.
  • Expected pattern: the slip rings give a trace that alternates about zero, the split ring gives humps that stay on one side of zero, and the peak potential difference and the frequency both rise as the rate of rotation rises.
  • Sources of uncertainty: hand cranking is uneven, the brushes may bounce or arc on the rings, the coil may not sit centrally between the poles, and reading a peak from a moving trace is imprecise.
  • Improvements: drive the coil with a motor rather than by hand, use a data logger to capture and average the peak values, and clean the brushes and rings so contact stays steady.
  • Safety: keep fingers and loose clothing away from the rotating coil and the drive belt, do not exceed the rated supply of the driving motor, and clamp the generator to the bench.

Reading a generator output trace

  1. Identify the machine first: a trace that crosses the zero line and goes negative is from an alternator, and a trace of humps all on one side of zero is from a dynamo.
  2. Read the peak potential difference by counting the vertical divisions from the zero line to the top of the trace and multiplying by the volts per division.
  3. Read the period by counting the horizontal divisions for one complete cycle and multiplying by the time per division.
  4. Convert the period into the rate of rotation using f=1Tf=\dfrac{1}{T}f=T1​, remembering that an alternator completes one cycle per rotation.
  5. A dynamo trace shows two humps per rotation, so its period must be measured over one complete pair of humps rather than one hump.
Example

Reading an alternator trace

  • An oscilloscope trace from an alternator shows one complete cycle across four horizontal divisions, with the timebase set to 5 ms5\ \text{ms}5 ms per division.
  • The trace reaches three vertical divisions above the zero line, with the sensitivity set to 4 V4\ \text{V}4 V per division.
  • The period is T=4×5 ms=20 ms=0.020 sT=4\times5\ \text{ms}=20\ \text{ms}=0.020\ \text{s}T=4×5 ms=20 ms=0.020 s.
  • The frequency is f=1T=10.020=50 Hzf=\dfrac{1}{T}=\dfrac{1}{0.020}=50\ \text{Hz}f=T1​=0.0201​=50 Hz, so the coil completes 505050 rotations each second.
  • The peak potential difference is 3×4=12 V3\times4=12\ \text{V}3×4=12 V.
  • Turning the coil twice as fast would give a period of 10 ms10\ \text{ms}10 ms, a frequency of 100 Hz100\ \text{Hz}100 Hz and a peak of about 24 V24\ \text{V}24 V.
Exam technique

Describing a generator

  • Name the connection first, slip rings for an alternator and a split-ring commutator for a dynamo, because that is the mark that separates the two machines.
  • Explain the output by saying that the coil sides cut field lines fastest when the coil is parallel to the field and cut none when it is at right angles to it.
  • When sketching an output, draw and label the zero line, then show two full cycles so the shape is unambiguous.
  • For a faster rotation, state both effects, a taller peak and a shorter period, since one alone is usually only half the marks.
  • Describe a dynamo output as direct but changing in size, rather than as steady.
Common Mistake
  • Do not describe a dynamo output as a smooth steady potential difference, because its size still rises and falls twice each rotation.
  • Do not swap the two connections, since slip rings keep the output alternating and a split ring makes it direct.
  • Do not say the induced potential difference is greatest when the coil is at right angles to the field lines, because that is where it is zero.
  • Do not confuse a generator with a motor, since a generator is turned to produce a potential difference while a motor is supplied with a current to produce rotation.
  • Do not claim that turning the coil faster changes only the frequency, because the peak potential difference rises as well.
Self review
  • State the part that makes an alternator produce an alternating output and the part that makes a dynamo produce a direct output.
  • Explain why the induced potential difference falls to zero twice during each rotation of the coil.
  • Sketch and label the output of an alternator and the output of a dynamo over two full rotations.
  • Calculate the frequency of an alternator whose output has a period of 25 ms25\ \text{ms}25 ms.
  • Describe two changes that raise the peak output of a generator without changing its frequency.

13.1.4 Microphones and loudspeakers

Microphones and the generator effect

Definition

Moving-coil microphone

A moving-coil microphone is a device that uses the generator effect to convert the pressure variations of a sound wave into a varying potential difference.

Definition

Generator effect

The generator effect is the induction of a potential difference in a conductor when there is relative movement between the conductor and a magnetic field.

  1. A moving-coil microphone has a thin flexible diaphragm fixed to a light coil of wire, and the coil sits in the field of a permanent magnet.
  2. A sound wave arriving at the diaphragm is a series of compressions, where the air pressure is above normal, and rarefactions, where it is below normal.
  3. The changing air pressure pushes the diaphragm inwards during a compression and lets it spring outwards during a rarefaction, so the diaphragm vibrates at the frequency of the sound.
  4. The coil is attached to the diaphragm, so the coil vibrates with it and moves back and forth inside the magnetic field.
  5. The moving coil changes the magnetic field passing through itself, so a potential difference is induced across the coil by the generator effect.
  6. The coil moves one way during a compression and the opposite way during a rarefaction, so the induced potential difference reverses each half cycle and the output is an alternating signal.
  7. A louder sound carries a larger pressure variation, which pushes the diaphragm further and faster, so the coil moves faster and the amplitude of the induced potential difference is larger.
  8. A higher-pitched sound vibrates the diaphragm more times each second, so the frequency of the electrical signal is higher.
  9. The signal therefore has the same frequency as the sound wave and an amplitude that follows its loudness, which is what makes it an accurate electrical copy of the sound.

Loudspeakers and the motor effect

Definition

Loudspeaker

A loudspeaker is a device that uses the motor effect to convert a varying electrical signal into a sound wave.

Definition

Motor effect

The motor effect is the force experienced by a current-carrying conductor when it is placed in a magnetic field that is not parallel to the current.

  1. A loudspeaker has a coil wound around one pole of a permanent magnet, and the coil is fixed to a stiff paper or plastic cone.
  2. An alternating current from an amplifier is passed through the coil, so the coil becomes a current-carrying conductor sitting in a magnetic field.
  3. A current-carrying conductor in a magnetic field experiences a force, so the coil is pushed along the axis of the magnet.
  4. The direction of the force reverses whenever the direction of the current reverses, so the coil is pushed outwards and then pulled inwards, once for each cycle of the current.
  5. The cone moves with the coil and pushes on the air in front of it, creating a compression as it moves out and a rarefaction as it moves back, and these travel outwards as a sound wave.
  6. A larger current amplitude produces a larger force, a larger cone movement and therefore a louder sound.
  7. A higher current frequency makes the cone vibrate more times each second, giving a higher-pitched sound of the same frequency as the current.
  8. Fleming's left-hand rule gives the direction of the force on the coil at any instant from the directions of the current and the field.

Comparing the two devices

  1. Effect used: a microphone works by the generator effect, in which movement induces a potential difference, and a loudspeaker works by the motor effect, in which a current produces a force.
  2. Direction of energy transfer: a microphone transfers energy from a sound wave to an electrical circuit, and a loudspeaker transfers energy from an electrical circuit to a sound wave.
  3. Input and output: the sound wave is the input to a microphone and the output from a loudspeaker.
  4. Shared parts: both devices contain a coil, a permanent magnet and a movable surface, so the two are close to being the same device operated in opposite directions.
  5. Signal matching: in both devices the frequency of the electrical signal equals the frequency of the sound, and the amplitude of the signal corresponds to the loudness.
  6. A small loudspeaker will in fact act as a rough microphone if sound is directed at its cone, because the moving coil then induces a potential difference.
Example

Following a signal from voice to speaker

  • Someone speaks into a microphone, and the pressure variations of their voice make the diaphragm and its attached coil vibrate at about 200 Hz200\ \text{Hz}200 Hz.
  • The vibrating coil induces an alternating potential difference of a few millivolts at 200 Hz200\ \text{Hz}200 Hz across its ends.
  • An amplifier increases the amplitude of this signal without changing its frequency, drawing the extra energy from its own power supply.
  • The amplified alternating current is passed through the coil of a loudspeaker, where the coil experiences a force that reverses 200200200 times each second.
  • The cone vibrates at 200 Hz200\ \text{Hz}200 Hz and pushes on the air, producing a sound wave of the same frequency as the original voice.
  • Speaking more loudly raises the amplitude at every stage, so the cone moves further and the sound produced is louder while the pitch stays the same.
Exam technique

Explaining a sound device

  • Name the effect at the start of the answer, generator effect for a microphone and motor effect for a loudspeaker, because the examiner is looking for that term.
  • Build the answer as an unbroken chain, from sound wave to diaphragm to coil to induced potential difference, or from current to force to cone to sound wave.
  • Link loudness to amplitude and pitch to frequency explicitly, rather than writing that the signal matches the sound.
  • When the question gives a mark tariff of six, write the chain in order and include one sentence on why the signal reverses direction each half cycle.
  • Use potential difference for the microphone output and current for the loudspeaker input, since swapping them loses the mark.
Common Mistake
  • Do not say that a microphone uses the motor effect, because in a microphone the movement comes first and the potential difference is induced by it.
  • Do not write that the coil in a loudspeaker moves because the magnet moves, since the magnet is fixed and the coil is pushed by the force on the current.
  • Do not confuse the amplitude of the signal with its frequency when explaining loudness and pitch.
  • Do not claim that a loudspeaker needs a direct current, because a steady current would hold the cone in one position and produce no sound.
  • Do not describe the diaphragm as being pulled by the sound wave, since a compression pushes it inwards and a rarefaction lets it move back out.
Self review
  • Describe how a moving-coil microphone converts a sound wave into an electrical signal.
  • Explain why the output of a microphone is an alternating potential difference rather than a direct one.
  • Describe how the coil and cone of a loudspeaker produce a sound wave from an alternating current.
  • State what happens to the sound from a loudspeaker when the amplitude of the current is increased.
  • State which effect each device uses and give the direction of energy transfer in each.

Recap questions

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A magnet is pushed into a coil connected to a galvanometer and then held still inside the coil. What does the galvanometer show while the magnet is held still?

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Electromagnetic Induction on a small scale

When we put a stationary wire inside a magnetic field, absolutely nothing happens. However, if we move that wire so that it cuts across magnetic field lines, a potential difference (voltage) is created across the ends of the wire.

This physical phenomenon is called electromagnetic induction. It is defined as the creation of a potential difference across an electrical conductor which is experiencing a change in magnetic field.

If this conductor is part of a complete circuit, the induced potential difference will cause an electric current to flow through the circuit. This is known as an induced current.

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An emergency relief worker uses a hand-cranked generator to charge a battery pack. Initially, when the battery is disconnected, the crank turns very easily at a constant speed. When the empty battery pack is connected to the generator and begins drawing current, the worker finds they must exert a significantly larger force to maintain the same constant rate of rotation.

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A wire is held stationary inside a magnetic field. What p.d. is induced?

13.1 Inducing current, generators and microphones Revision Guide

  1. GCSE
  2. /Physics
  3. /13.1 Inducing current, generators and microphones

Revision notes for Edexcel GCSE Physics 13.1 Inducing current, generators and microphones. Open the guide for explanations and worked examples. Written against the Edexcel GCSE Physics (1PH0) specification, so the content matches what's examinable rather than general Physics background.