An alternator produces a peak potential difference of 4.0 V at 20 Hz. Its speed of rotation is doubled. The peak potential difference is proportional to the speed.
What is the new output?
Peak potential difference 8.0 V8.0\ \mathrm{V}8.0 V; frequency 20 Hz20\ \mathrm{Hz}20 Hz.
Peak potential difference 4.0 V4.0\ \mathrm{V}4.0 V; frequency 40 Hz40\ \mathrm{Hz}40 Hz.
Peak potential difference 8.0 V8.0\ \mathrm{V}8.0 V; frequency 40 Hz40\ \mathrm{Hz}40 Hz.
Peak potential difference 4.0 V4.0\ \mathrm{V}4.0 V; frequency 20 Hz20\ \mathrm{Hz}20 Hz.
92 exam-style questions on Edexcel GCSE Physics 13.1 Inducing a current, covering 13.1.1 Producing an electric current by induction, 13.1.2 Factors affecting the induced potential difference, 13.1.3 Alternators and dynamos, and 13.1.4 Microphones and loudspeakers. Each one has a worked solution and a mark scheme showing where the marks go.