A liquid has a specific heat capacity of 2000 J kg−1 ∘C−12000\ \mathrm{J\,kg^{-1}\,{}^\circ C^{-1}}2000 Jkg−1∘C−1. What energy is needed to raise the temperature of 0.50 kg of the liquid by 6.0 ∘C6.0\ ^\circ\mathrm{C}6.0 ∘C? Use ΔQ=mcΔθ\Delta Q=mc\Delta\thetaΔQ=mcΔθ.
12000 J12000\ \mathrm{J}12000 J
24000 J24000\ \mathrm{J}24000 J
1000 J1000\ \mathrm{J}1000 J
6000 J6000\ \mathrm{J}6000 J
110 exam-style questions on Edexcel GCSE Physics 14.2 Specific heat capacity and latent heat, covering 14.2.1 Heating, temperature and changes of state, 14.2.2 Specific heat capacity and specific latent heat, 14.2.3 Specific heat capacity calculation, 14.2.4 Specific latent heat calculation, and 14.2.5 Reducing energy transfer through thermal insulation. Each one has a worked solution and a mark scheme showing where the marks go.