A jeweller uses an electric crucible to melt 0.030 kg of a copper alloy that is already at its melting point. The specific latent heat of fusion of the alloy is 2.0 × 105 J/kg. The crucible transfers 80% of the electrical energy supplied to it to the alloy. Use Q=mLQ=mLQ=mL.
What is the electrical energy supplied to the crucible?
4.8×103 J4.8\times10^3\ \mathrm{J}4.8×103 J
7.5×103 J7.5\times10^3\ \mathrm{J}7.5×103 J
6.0×103 J6.0\times10^3\ \mathrm{J}6.0×103 J
3.0×104 J3.0\times10^4\ \mathrm{J}3.0×104 J
110 exam-style questions on Edexcel GCSE Physics 14.2 Specific heat capacity and latent heat, covering 14.2.1 Heating, temperature and changes of state, 14.2.2 Specific heat capacity and specific latent heat, 14.2.3 Specific heat capacity calculation, 14.2.4 Specific latent heat calculation, and 14.2.5 Reducing energy transfer through thermal insulation. Each one has a worked solution and a mark scheme showing where the marks go.