A student records the following results for a fixed mass of gas.
| Reading | Pressure in kPa\mathrm{kPa}kPa | Volume in cm3\mathrm{cm^3}cm3 |
|---|---|---|
| P | 100 | 60 |
| Q | 150 | 40 |
| R | 240 | 30 |
All measurements are accurate. P and Q are at the same temperature. R is recorded immediately after rapid compression.
Which statement best explains reading R?
The pressure–volume product is greater because compression has increased the gas mass.
The pressure–volume product is smaller because work has decreased the gas temperature.
The pressure–volume product is greater because work has increased the gas temperature.
The pressure–volume product is unchanged because compression has left temperature unchanged.
108 exam-style questions on Edexcel GCSE Physics 14.3 Gas pressure and temperature, covering 14.3.1 Gas pressure and particle motion, 14.3.2 Temperature and pressure at constant volume, 14.3.3 Absolute zero and the kelvin scale, 14.3.4 Compressing and expanding gases, 14.3.5 Volume and pressure at constant temperature, and 14.3.6 Doing work on a gas. Each one has a worked solution and a mark scheme showing where the marks go.