A spring obeys Hooke's law. A force of 5.0 N extends it by 25 mm. The force is increased to 8.0 N. Use F=kxF=kxF=kx and E=12kx2\displaystyle E=\frac{1}{2}kx^2E=21kx2. What additional work is done in increasing the force?
0.1600 J0.1600\ \mathrm{J}0.1600 J
0.2225 J0.2225\ \mathrm{J}0.2225 J
0.0975 J0.0975\ \mathrm{J}0.0975 J
0.0225 J0.0225\ \mathrm{J}0.0225 J
102 exam-style questions on Edexcel GCSE Physics 15.1 Forces and springs, covering 15.1.1 Elastic and inelastic distortion, 15.1.2 The spring constant, 15.1.3 Work done in stretching a spring, and 15.1.4 Linear and non-linear force–extension. Each one has a worked solution and a mark scheme showing where the marks go.