Energy stores, transfers and conservation

EasyMediumHard
123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081
Question 38
Easy

Figure 1 shows a funicular railway car descending a steep incline from the upper mountain station to the valley floor.

Funicular railway car descending a mountain incline

The mass of the funicular carriage, m=1250 kgm = 1250 \text{ kg}m=1250 kg.

The change in vertical height, h=85.0 mh = 85.0 \text{ m}h=85.0 m.

Gravitational field strength, g=9.8 N/kgg = 9.8 \text{ N/kg}g=9.8 N/kg.

Calculate the change in gravitational potential energy for the funicular carriage. Use the equation:

change in gravitational potential energy=mass×gravitational field strength×change in height \text{change in gravitational potential energy} = \text{mass} \times \text{gravitational field strength} \times \text{change in height} change in gravitational potential energy=mass×gravitational field strength×change in height
[2]

Energy stores, transfers and conservation Questions

  1. GCSE
  2. /Physics
  3. /Energy stores, transfers and conservation