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8 Energy – forces doing work

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Question 27

During a museum refit, a wheeled display cabinet is moved along a straight guide rail. A constant force of 16 N acts along the rail. The position sensor reads 125 cm before the movement and 175 cm afterwards.

A trainee records the work done as

$JE=16\div(175-125)=0.32\ \mathrm{J}$

By what factor must the trainee's value be multiplied to obtain the correct work done?

[1]

A

$100$

B

$125\dfrac{1}{25}$

C

$25$

D

$2500$

Markscheme

8 Energy – forces doing work Questions

GCSE
Physics
8 Energy – forces doing work

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