A refrigeration engineer checks a heat-transfer liquid. The engineer places an empty cup on a balance and resets the balance to zero before adding the liquid.
| Volume of liquid added | Balance reading |
|---|---|
| 50 cm3 | 55 g |
Use
1 g=1×10−3 kg1\ \mathrm{g}=1\times10^{-3}\ \mathrm{kg}1 g=1×10−3 kg
1 cm3=1×10−6 m31\ \mathrm{cm^3}=1\times10^{-6}\ \mathrm{m^3}1 cm3=1×10−6 m3
What calculation gives the density of the liquid in kg/m3\mathrm{kg/m^3}kg/m3?
50×10−655×10−3 kg/m3\dfrac{50\times10^{-6}}{55\times10^{-3}}\ \mathrm{kg/m^3}55×10−350×10−6 kg/m3
55×10−350×10−6 kg/m3\dfrac{55\times10^{-3}}{50\times10^{-6}}\ \mathrm{kg/m^3}50×10−655×10−3 kg/m3
5550×10−6 kg/m3\dfrac{55}{50\times10^{-6}}\ \mathrm{kg/m^3}50×10−655 kg/m3
55×10−350 kg/m3\dfrac{55\times10^{-3}}{50}\ \mathrm{kg/m^3}5055×10−3 kg/m3
87 exam-style questions on Edexcel GCSE Physics 14.1 Density and states of matter, covering 14.1.1 Kinetic theory and states of matter, 14.1.2 Density, and 14.1.3 Density and changes of state. Each one has a worked solution and a mark scheme showing where the marks go.