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Converting units, significant figures and standard form

Converting units, significant figures and standard form

1.1.2 Unit prefixes, conversions, significant figures and standard form

Unit prefixes

Definition

Unit prefix

A unit prefix is a symbol placed before a unit to show that the unit has been multiplied by a power of ten, such as kilo for one thousand or milli for one thousandth.

  1. Giga, symbol G\text{G}G, means ×109\times 10^{9}×109, so 1 GW=1×109 W1\ \text{GW}=1\times10^{9}\ \text{W}1 GW=1×109 W.
  2. Mega, symbol M\text{M}M, means ×106\times 10^{6}×106, so 1 MJ=1×106 J1\ \text{MJ}=1\times10^{6}\ \text{J}1 MJ=1×106 J.
  3. Kilo, symbol k\text{k}k, means ×103\times 10^{3}×103, so 1 km=1×103 m1\ \text{km}=1\times10^{3}\ \text{m}1 km=1×103 m.
  4. Centi, symbol c\text{c}c, means ×10−2\times 10^{-2}×10−2, so 1 cm=1×10−2 m1\ \text{cm}=1\times10^{-2}\ \text{m}1 cm=1×10−2 m.
  5. Milli, symbol m\text{m}m, means ×10−3\times 10^{-3}×10−3, so 1 mA=1×10−3 A1\ \text{mA}=1\times10^{-3}\ \text{A}1 mA=1×10−3 A.
  6. Micro, symbol μ\muμ, means ×10−6\times 10^{-6}×10−6, so 1 μC=1×10−6 C1\ \mu\text{C}=1\times10^{-6}\ \text{C}1 μC=1×10−6 C.
  7. Nano, symbol n\text{n}n, means ×10−9\times 10^{-9}×10−9, so 1 nm=1×10−9 m1\ \text{nm}=1\times10^{-9}\ \text{m}1 nm=1×10−9 m.
  8. To remove a prefix, multiply the numerical value by the prefix factor, and to introduce a prefix, divide by that factor.
Example
  • A current of 850 mA850\ \text{mA}850 mA is converted using milli =10−3=10^{-3}=10−3.
  • 850 mA=850×10−3 A=0.850 A850\ \text{mA}=850\times10^{-3}\ \text{A}=0.850\ \text{A}850 mA=850×10−3 A=0.850 A.
  • A power of 2.4×106 W2.4\times10^{6}\ \text{W}2.4×106 W is converted using mega =106=10^{6}=106.
  • 2.4×106 W=2.4 MW2.4\times10^{6}\ \text{W}=2.4\ \text{MW}2.4×106 W=2.4 MW.

Converting units

Definition

Unit conversion

A unit conversion changes the unit used to express a quantity without changing the physical quantity itself.

  1. Convert values to the units required by the equation before substitution, because a correct equation with inconsistent units gives an incorrect number.
  2. 1 minute=60 s1\ \text{minute}=60\ \text{s}1 minute=60 s and 1 hour=3600 s1\ \text{hour}=3600\ \text{s}1 hour=3600 s.
  3. Convert hours to seconds by multiplying by 360036003600, and convert seconds to hours by dividing by 360036003600.
  4. 1 m=100 cm=1000 mm1\ \text{m}=100\ \text{cm}=1000\ \text{mm}1 m=100 cm=1000 mm.
  5. 1 kg=1000 g1\ \text{kg}=1000\ \text{g}1 kg=1000 g, so grams are converted to kilograms by dividing by 100010001000.
  6. Converting to a smaller unit gives a larger numerical value, while converting to a larger unit gives a smaller numerical value.

Converting compound units

  1. A compound unit contains more than one unit, so every part of the unit must be converted.
  2. For speed, 1 km/h=1000 m3600 s=13.6 m/s1\ \text{km/h}=\dfrac{1000\ \text{m}}{3600\ \text{s}}=\dfrac{1}{3.6}\ \text{m/s}1 km/h=3600 s1000 m​=3.61​ m/s.
  3. Convert kilometres per hour to metres per second by dividing by 3.63.63.6, and convert metres per second to kilometres per hour by multiplying by 3.63.63.6.
  4. For squared and cubed units, the conversion factor must also be squared or cubed, so 1 cm2=(10−2 m)2=10−4 m21\ \text{cm}^{2}=(10^{-2}\ \text{m})^{2}=10^{-4}\ \text{m}^{2}1 cm2=(10−2 m)2=10−4 m2.
  5. Likewise, 1 cm3=(10−2 m)3=10−6 m31\ \text{cm}^{3}=(10^{-2}\ \text{m})^{3}=10^{-6}\ \text{m}^{3}1 cm3=(10−2 m)3=10−6 m3.
Example
  • A journey time of 1.75 h1.75\ \text{h}1.75 h is converted by multiplying by 360036003600.
  • t=1.75×3600=6300 st=1.75\times3600=6300\ \text{s}t=1.75×3600=6300 s.
  • A speed of 126 km/h126\ \text{km/h}126 km/h is converted by dividing by 3.63.63.6.
  • v=126÷3.6=35.0 m/sv=126\div3.6=35.0\ \text{m/s}v=126÷3.6=35.0 m/s.

Standard form

Definition

Standard form

Standard form writes a number as A multiplied by ten to the power n, where A is between 1 and 10 and n is an integer.

  1. Move the decimal point until exactly one non-zero digit remains before it, then use the number of places moved as the magnitude of the power.
  2. A large number has a positive power, such as 6 500 000=6.5×1066\,500\,000=6.5\times10^{6}6500000=6.5×106.
  3. A number between zero and one has a negative power, such as 0.000 000 45=4.5×10−70.000\,000\,45=4.5\times10^{-7}0.00000045=4.5×10−7.
  4. When multiplying standard-form values, multiply the leading numbers and add the powers, then rewrite the result so the leading number lies between 111 and 101010.
  5. When dividing standard-form values, divide the leading numbers and subtract the powers, then normalise the result.
Example
  • (3.0×108)(2.0×10−6)=(3.0×2.0)×108−6(3.0\times10^{8})(2.0\times10^{-6})=(3.0\times2.0)\times10^{8-6}(3.0×108)(2.0×10−6)=(3.0×2.0)×108−6.
  • The result is 6.0×1026.0\times10^{2}6.0×102.
  • 8.4×1072.0×103=8.42.0×107−3\dfrac{8.4\times10^{7}}{2.0\times10^{3}}=\dfrac{8.4}{2.0}\times10^{7-3}2.0×1038.4×107​=2.08.4​×107−3.
  • The result is 4.2×1044.2\times10^{4}4.2×104.

Significant figures

Definition

Significant figures

Significant figures are the digits in a number that show its measured precision, starting from the first non-zero digit.

  1. All non-zero digits are significant, and zeros between significant digits are also significant.
  2. Zeros before the first non-zero digit are not significant, so 0.004560.004560.00456 has three significant figures.
  3. Trailing zeros after a decimal point are significant, so 2.502.502.50 has three significant figures.
  4. To round to a stated number of significant figures, keep the required digits and inspect the next digit.
  5. If the next digit is 555 or more, increase the last retained digit by one, and if it is below 555, leave the last retained digit unchanged.
  6. Keep unrounded calculator values during working and round only the final answer.
Example
  • The value 0.0078640.0078640.007864 rounded to three significant figures keeps 777, 888 and 666.
  • The next digit is 444, so the rounded value is 0.007860.007860.00786.
  • The value 58 74658\,74658746 rounded to three significant figures keeps 555, 888 and 777.
  • The next digit is 444, so the rounded value is 58 70058\,70058700, or 5.87×1045.87\times10^{4}5.87×104.
Example
  • A train moves at 126 km/h126\ \text{km/h}126 km/h for 1 h 45 min1\ \text{h}\ 45\ \text{min}1 h 45 min.
  • Convert the speed: 126÷3.6=35.0 m/s126\div3.6=35.0\ \text{m/s}126÷3.6=35.0 m/s.
  • Convert the time: (1×3600)+(45×60)=6300 s(1\times3600)+(45\times60)=6300\ \text{s}(1×3600)+(45×60)=6300 s.
  • Use d=vtd=vtd=vt to obtain d=35.0×6300=220 500 md=35.0\times6300=220\,500\ \text{m}d=35.0×6300=220500 m.
  • Write the result in standard form and round to three significant figures: d=2.21×105 md=2.21\times10^{5}\ \text{m}d=2.21×105 m.
Common Mistake
  • Do not confuse lower-case m\text{m}m for milli with upper-case M\text{M}M for mega.
  • Do not treat significant figures as decimal places, because 0.004560.004560.00456 to two significant figures is 0.00460.00460.0046.
  • Do not convert cm2\text{cm}^{2}cm2 or cm3\text{cm}^{3}cm3 using only the linear factor.
  • Do not round intermediate calculator values, because early rounding can change the final answer.
Exam technique
  • Write each conversion on a separate line before substitution so that the method remains clear if later arithmetic is incorrect.
  • Check the requested output unit before calculating, because the final conversion may carry a separate mark.
  • Give the answer to the stated number of significant figures, or use the precision of the supplied data when the question asks for an appropriate value.
  • Include the final unit and use the expected size of the answer as a conversion check.
Self review
  • What powers of ten correspond to giga, mega, kilo, centi, milli, micro and nano?
  • How are kilometres per hour converted to metres per second?
  • What conditions must AAA and nnn satisfy in standard form?
  • Which zeros count as significant figures?
  • Why should rounding be left until the final line?

Recap questions

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A wire is 3.6 m long. What is its length in centimetres?

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Conversion map for km, m, cm, mm, kg, g, h, min and s, plus a worked example converting 36 km/h to 10 m/s

Physics equations usually work best when every value is in SI units such as metres, kilograms and seconds. A physical quantity is what you measure, and the unit tells you the scale of that measurement.

Metric prefixes tell you how a unit compares with the base unit. For example, 1 km=1000 m1 \text{ km} = 1000 \text{ m}1 km=1000 m, 1 m=100 cm1 \text{ m} = 100 \text{ cm}1 m=100 cm, 1 m=1000 mm1 \text{ m} = 1000 \text{ mm}1 m=1000 mm and 1 kg=1000 g1 \text{ kg} = 1000 \text{ g}1 kg=1000 g.

When you change from a bigger unit to a smaller unit, the number gets bigger, so you multiply. When you change from a smaller unit to a bigger unit, the number gets smaller, so you divide. Mass is a common trap because questions often give grams but equations usually want kilograms.

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The mass of a particular virus particle is estimated to be 2.4 × 10-18 kg.

The mass of a small bacterium is estimated to be 8.0 × 10-16 kg.

Calculate the value of

mass of the virus particlemass of the bacterium \frac{\text{mass of the virus particle}}{\text{mass of the bacterium}} mass of the bacteriummass of the virus particle​

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What are the standard SI units for mass, distance, and time?

1.1.2 Converting units, significant figures and standard form Revision Guide

  1. GCSE
  2. /Physics
  3. /1.1.2 Converting units, significant figures and standard form

Revision notes for Edexcel GCSE Physics 1.1.2 Converting units, significant figures and standard form. Open the guide for explanations and worked examples. Written against the Edexcel GCSE Physics (1PH0) specification, so the content matches what's examinable rather than general Physics background.