- How the structure of the atom links to electric charge.
- How to draw and interpret simple circuit diagrams using GCSE symbols.
- What current and potential difference mean, and how to calculate with Q=I×tQ = I \times tQ=I×t and E=Q×VE = Q \times VE=Q×V.
- How resistance affects current, including series and parallel circuits.
Everything in a circuit is made from atoms. An atom has a tiny central nucleus, with electrons around the outside.

Subatomic particles
An atom contains three main particles:
- Protons: in the nucleus, positive charge, relative mass 1.
- Neutrons: in the nucleus, no charge, relative mass 1.
- Electrons: outside the nucleus, negative charge, very small relative mass.
Electricity happens because charge can move. In metal wires, the moving charged particles are electrons.
Charge in metals
In a metal circuit, current is caused by electrons moving through the metal. Electrons are negatively charged.
A neutral atom has equal numbers of protons and electrons, so the positive and negative charges balance overall.
A circuit is a path that allows electric charge to flow. In GCSE Physics, we draw circuits using standard symbols, not pictures of real components.
A cell is a source of potential difference; the long line is the positive terminal and the short line is the negative terminal. A battery is two or more cells joined together.

Component
A component is any part of a circuit, such as a lamp, resistor, motor, diode, ammeter or voltmeter.
Important components include:
- A switch, which opens or closes the circuit.
- A resistor, which makes it harder for current to flow.
- A variable resistor, whose resistance can be changed.
- A lamp, which transfers electrical energy to light and thermal energy.
- A motor, which transfers electrical energy to kinetic energy.
- A diode, which allows current to flow easily in one direction only.
- An LED, which is a light-emitting diode.
- A thermistor, whose resistance changes with temperature.
- An LDR, or light-dependent resistor, whose resistance changes with light intensity.
For a current to flow, the circuit must be closed and must include a source of potential difference, such as a cell or battery.
Closed circuit
A closed circuit is a complete conducting loop with no gaps. If a switch is open, the circuit is broken and there is no current.
A source of potential difference gives charges energy. If there is a complete path, the charges move around the circuit.
Open switch means no current
An open switch is a gap in the circuit. Even if a battery is connected, charge cannot keep flowing around the circuit, so the current is zero.
Electric current tells you how quickly charge is flowing.
Current
Current is the rate of flow of charge. It is measured in amperes, often shortened to amps (A).
The equation is:
Q=I×tQ = I \times tQ=I×t
where:
- QQQ is charge in coulombs (C)
- III is current in amps (A)
- ttt is time in seconds (s)
You need to recall and use this equation.
Calculating charge from current and time
A lamp has a current of 0.40 A through it for 30 s. Calculate the charge that flows.
- Choose the correct equation because the question gives current and time: Q=I×tQ = I \times tQ=I×t.
- Substitute the values with units: Q=0.40 A×30 sQ = 0.40\ \text{A} \times 30\ \text{s}Q=0.40 A×30 s.
- Calculate the charge: Q=12 CQ = 12\ \text{C}Q=12 C.
What one amp means
A current of 1 A means 1 coulomb of charge passes a point every second.
Potential difference is often called voltage. It tells you how much energy is transferred by each coulomb of charge.
Potential difference
Potential difference is the energy transferred per unit charge passed. It is measured in volts (V).
One volt means one joule per coulomb:
1 V=1 J/C1\ \text{V} = 1\ \text{J/C}1 V=1 J/C
The equation is:
E=Q×VE = Q \times VE=Q×V
where:
- EEE is energy transferred in joules (J)
- QQQ is charge in coulombs (C)
- VVV is potential difference in volts (V)
You need to recall and use this equation.
Calculating energy transferred by charge
A charge of 5.0 C passes through a motor with a potential difference of 12 V across it. Calculate the energy transferred.
- Use the energy equation because the question gives charge and potential difference: E=Q×VE = Q \times VE=Q×V.
- Substitute the values: E=5.0 C×12 VE = 5.0\ \text{C} \times 12\ \text{V}E=5.0 C×12 V.
- Calculate the energy transferred: E=60 JE = 60\ \text{J}E=60 J.
An ammeter measures current. It must be connected in series with the component, so the same current passes through the ammeter and the component.
A voltmeter measures potential difference. It must be connected in parallel across the component, so it compares the energy difference between the two ends of that component.

Choosing where to place meters
You want to measure the current through a resistor and the potential difference across it.
- For current, the ammeter must be part of the same path as the resistor, so place the ammeter in series with the resistor.
- For potential difference, the voltmeter must compare the two sides of the resistor, so connect it in parallel across the resistor.
- Check the circuit still has a complete loop through the cell, ammeter and resistor; the voltmeter is on a separate parallel connection across the resistor.
Mixing up meters
Ammeters go in series. Voltmeters go in parallel. If you swap them, the circuit reading will be wrong and the circuit may not work as intended.
A series circuit has only one path for current. All components are on the same loop.
A parallel circuit has more than one path for current. Each separate path is called a branch.
In a series circuit:
- The current is the same through every component.
- The potential difference from the source is shared between components.
- If one component breaks or a switch opens, the whole circuit stops.
In a parallel circuit:
- The current splits between branches.
- The current rejoins after the branches.
- Components in different branches can still work if one branch is broken.
- Each branch has the same potential difference as the supply, if connected directly across it.
Current at a junction
Current is conserved at a junction. The total current going into a junction equals the total current coming out.
Using current conservation at a junction
A current of 3.0 A reaches a junction. One branch has a current of 1.2 A. Find the current in the other branch.
- Apply conservation of current: total current into the junction equals total current out.
- Set up the relationship: 3.0 A=1.2 A+I23.0\ \text{A} = 1.2\ \text{A} + I_23.0 A=1.2 A+I2.
- Rearrange and calculate: I2=3.0 A−1.2 A=1.8 AI_2 = 3.0\ \text{A} - 1.2\ \text{A} = 1.8\ \text{A}I2=3.0 A−1.2 A=1.8 A.
Resistance is how much a component opposes the flow of current. It is measured in ohms (Ω).
Resistance
Resistance is the opposition to current in a circuit. A higher resistance makes it harder for charge to flow.
The equation linking potential difference, current and resistance is:
V=I×RV = I \times RV=I×R
where:
- VVV is potential difference in volts (V)
- III is current in amps (A)
- RRR is resistance in ohms (Ω)
You need to recall and use this equation.
For a fixed potential difference, increasing the resistance decreases the current. Decreasing the resistance increases the current.
Calculating current from potential difference and resistance
A resistor has a potential difference of 6.0 V across it and a resistance of 12 Ω. Calculate the current.
- Rearrange V=I×RV = I \times RV=I×R to make current the subject: I=VRI = \frac{V}{R}I=RV.
- Substitute the values: I=6.0 V12 ΩI = \frac{6.0\ \text{V}}{12\ \Omega}I=12 Ω6.0 V.
- Calculate the current: I=0.50 AI = 0.50\ \text{A}I=0.50 A.
A variable resistor lets you change the resistance in a circuit. This changes the current. For example, increasing the resistance of a variable resistor reduces the current through a lamp, making the lamp dimmer.
Sanity check for resistance questions
If the same battery is used, a bigger resistance should give a smaller current. If your answer does the opposite, check your rearrangement.
When resistors are in series, the current has to pass through each resistor one after another. Each resistor makes it harder for current to flow, so the total resistance increases.
When resistors are in parallel, there is more than one route for charge to take. This makes it easier for current to flow overall, so the total resistance decreases.
Resistors together
- In series, adding another resistor increases the total resistance.
- In parallel, adding another resistor decreases the total resistance because it adds another path for current.
Thinking more resistors always means more resistance
More resistors only definitely means more total resistance when they are in series. In parallel, adding another branch can reduce the total resistance.
In the exam
- Before using an equation, identify what the question is asking for: charge, current, time, energy, potential difference or resistance.
- Draw or trace the circuit path: ammeters go in series, voltmeters go in parallel, and current is conserved at junctions.
- Check your units carefully: time in seconds, charge in coulombs, current in amps, potential difference in volts, resistance in ohms, energy in joules.
Check yourself
- Why must an ammeter be connected in series with the component it measures?
- A current of 2.0 A flows for 15 s. What equation would you use to find the charge moved?
- In a parallel circuit, what happens to the current at a junction?