A child moves down a playground slide. The child slows down on a horizontal section at the bottom of the slide.
State the force that acts against the movement of the child.
Explain the energy transfers while the child is slowing down on the horizontal section. Use your answer to part (a).
The work done by the force you identified in part (a) is 150 J as the child moves 5.0 m along the horizontal section.
Use the equation:
F=WsF = \dfrac{W}{s}F=sW
Calculate the average magnitude of this force.
113 exam-style questions on AQA GCSE Physics 5.2 Work done and energy transfer, covering 5.2 Work done and energy transfer. Each one has a worked solution and a mark scheme showing where the marks go.