The equation W=FsW = FsW=Fs links the work done WWW, the force F F\,F and the distance moved sss.
Which rearrangement of this equation is correct?
F=WsF = \dfrac{W}{s}F=sW
F=W×sF = W \times sF=W×s
F=sWF = \dfrac{s}{W}F=Ws
F=W+sF = W + sF=W+s
40 exam-style questions on AQA GCSE Physics 5.2 Work done and energy transfer, covering 5.2 Work done and energy transfer. Each one has a worked solution and a mark scheme showing where the marks go.