Table 1 shows data about four moons of a gas giant planet.
| Moon | Mean distance from the planet (km\text{km}km) | Time taken for one orbit (days\text{days}days) |
|---|---|---|
| Moon A | 120 000120\,000120000 | 1.51.51.5 |
| Moon B | 240 000240\,000240000 | 4.24.24.2 |
| Moon C | 360 000360\,000360000 | 7.87.87.8 |
| Moon D | 480 000480\,000480000 | 12.012.012.0 |
Describe the relationship between the mean distance from the planet and the time taken for one orbit.
Calculate the orbital speed of Moon B in km/day\text{km/day}km/day. Use the equation:
orbital speed=2π×mean distancetime taken for one orbit \text{orbital speed} = \frac{2\pi \times \text{mean distance}}{\text{time taken for one orbit}} orbital speed=time taken for one orbit2π×mean distanceGive your answer to 3 significant figures.
19 exam-style questions on AQA GCSE Physics 8.1 Solar system; stability of orbital motions; satellites, covering 8.1.1 Our solar system, 8.1.2 The life cycle of a star, and 8.1.3 Orbital motion, natural and artificial satellites. Each one has a worked solution and a mark scheme showing where the marks go.