Two identical lamps are connected in series with a 6.0 V battery.
The potential difference across one of the lamps is 3.0 V. Give the potential difference across the other lamp.
The current in the battery is 0.25 A. Write down the current in each lamp.
Calculate the resistance of one of the lamps. Use the equation: potential difference=current×resistance\text{potential difference} = \text{current} \times \text{resistance}potential difference=current×resistance
Give one change the student could make to increase the current in this circuit.
38 exam-style questions on AQA GCSE Physics 2.2 Series and parallel circuits, covering 2.2 Series and parallel circuits. Each one has a worked solution and a mark scheme showing where the marks go.