A spring has a spring constant of 40 N/m. The spring is stretched by 0.50 m. Use the equation Ee=0.5×spring constant×(extension)2E_e = 0.5 \times \text{spring constant} \times (\text{extension})^2Ee=0.5×spring constant×(extension)2 to find the elastic potential energy stored in the spring.
10 J
20 J
5.0 J
1.0 J
40 exam-style questions on AQA GCSE Physics 5.3 Forces and elasticity, covering 5.3 Forces and elasticity. Each one has a worked solution and a mark scheme showing where the marks go.