An elastic cord in a luggage restraint is stretched without exceeding its limit of proportionality. The force applied to the cord is FFF, its spring constant is k k\,k and its extension is eee.
Which equation should be used to calculate the extension of the cord?
e=F×ke = F \times ke=F×k
e=F÷ke = F \div ke=F÷k
e=F÷ke = \sqrt{F \div k}e=F÷k
e=k÷Fe = k \div Fe=k÷F
106 exam-style questions on AQA GCSE Physics 5.3 Forces and elasticity, covering 5.3 Forces and elasticity. Each one has a worked solution and a mark scheme showing where the marks go.