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5.6.1a Distance and displacement

5.6.1a Distance and displacement

Distance

Definition

Distance

Distance is how far an object moves along its path; it does not include direction.

  1. Distance is a scalar quantity: it has magnitude but no direction. A runner who completes 100 m100\ \text{m}100 m of a race has travelled a distance of 100 m100\ \text{m}100 m, whatever the direction.
  2. The SI unit is the metre (m\text{m}m); distance can also be given in kilometres (km\text{km}km) or centimetres (cm\text{cm}cm).
  3. The total distance for a journey is the sum of the lengths of all parts of the route.
  4. Distance cannot be negative: even if an object moves back towards its start, every part of the journey adds to the total.

Displacement

Definition

Displacement

Displacement is the straight-line distance from an object’s start point to its finish point, together with the direction of that straight line.

  1. Displacement is a vector quantity with both a magnitude (the straight-line distance between start and finish) and a direction (such as north, south, east or west).
  2. Its magnitude is measured in metres (m\text{m}m).
  3. The route does not affect displacement; only the start and finish positions matter, so an object can travel a large distance but have a small displacement.
  4. If an object finishes where it started, its displacement is zero, even though it may have travelled a considerable distance.

Comparing distance and displacement

  1. Distance adds up the actual route travelled; displacement compares the final position with the start and includes a direction.

distance-vs-displacement-curved-path-length-compared-to-straight-line-separation-3b514283-genie.png

Example

A student walks 40 m40\ \text{m}40 m east and then 15 m15\ \text{m}15 m west. Calculate the distance travelled and state the displacement.

  1. Find the distance by adding the lengths: distance=40 m+15 m=55 m\text{distance} = 40\ \text{m} + 15\ \text{m} = 55\ \text{m}distance=40 m+15 m=55 m.
  2. Taking east as positive, find the displacement magnitude: 40 m−15 m=25 m40\ \text{m} - 15\ \text{m} = 25\ \text{m}40 m−15 m=25 m.
  3. Add the direction: the student finishes east of the start, so displacement = 25 m25\ \text{m}25 m east.
  4. So the student travels a distance of 55 m55\ \text{m}55 m but has a displacement of 25 m25\ \text{m}25 m east.
Exam technique
  1. Do not assume distance and displacement are always equal: distance follows the actual route, displacement is the straight line from start to finish.
  2. A displacement answer is incomplete with only a magnitude; always give the direction.
  3. Returning to the start gives zero displacement, not zero distance.
  4. Match the command word: for distance, give the full route length with no direction; for displacement, give the straight-line change with magnitude and direction.
  5. In a comparison, use the terms scalar and vector: distance is a scalar, displacement is a vector.
Self review
  1. Define distance.
  2. Why is distance a scalar?
  3. What two things must a displacement include?
  4. What is the displacement of an object that finishes at its start point?
  5. Can an object’s distance be greater than the magnitude of its displacement?
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Distance is how far an object travels along its actual route. It is a scalar quantity, so it has magnitude but no direction, and it cannot be negative.

Displacement is the straight-line change from an object’s start point to its finish point, together with the direction of that line. It is a vector quantity, so a complete displacement answer needs both a magnitude and a direction.

The SI unit for both distance and displacement magnitude is the metre, m\text{m}m. Other common units include kilometres, km\text{km}km, and centimetres, cm\text{cm}cm.

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Why is distance a scalar quantity?

5.6.1a Distance and displacement Revision Guide

  1. GCSE
  2. /Physics
  3. /5.6.1a Distance and displacement