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5.6.1a Distance and displacement

Distance

Definition

Distance

Distance is how far an object moves along its path; it does not include direction.

  1. Distance is a scalar quantity: it has magnitude but no direction. A runner who completes 100 m100\ \text{m}100 m of a race has travelled a distance of 100 m100\ \text{m}100 m, whatever the direction.
  2. The SI unit is the metre (m\text{m}m); distance can also be given in kilometres (km\text{km}km) or centimetres (cm\text{cm}cm).
  3. The total distance for a journey is the sum of the lengths of all parts of the route.
  4. Distance cannot be negative: even if an object moves back towards its start, every part of the journey adds to the total.

Displacement

Definition

Displacement

Displacement is the straight-line distance from an object’s start point to its finish point, together with the direction of that straight line.

  1. Displacement is a vector quantity with both a magnitude (the straight-line distance between start and finish) and a direction (such as north, south, east or west).
  2. Its magnitude is measured in metres (m\text{m}m).
  3. The route does not affect displacement; only the start and finish positions matter, so an object can travel a large distance but have a small displacement.
  4. If an object finishes where it started, its displacement is zero, even though it may have travelled a considerable distance.

Comparing distance and displacement

  1. Distance adds up the actual route travelled; displacement compares the final position with the start and includes a direction.

distance-vs-displacement-curved-path-length-compared-to-straight-line-separation-3b514283-genie.png

Example

A student walks 40 m40\ \text{m}40 m east and then 15 m15\ \text{m}15 m west. Calculate the distance travelled and state the displacement.

  1. Find the distance by adding the lengths: distance=40 m+15 m=55 m\text{distance} = 40\ \text{m} + 15\ \text{m} = 55\ \text{m}distance=40 m+15 m=55 m.
  2. Taking east as positive, find the displacement magnitude: 40 m−15 m=25 m40\ \text{m} - 15\ \text{m} = 25\ \text{m}40 m−15 m=25 m.
  3. Add the direction: the student finishes east of the start, so displacement = 25 m25\ \text{m}25 m east.
  4. So the student travels a distance of 55 m55\ \text{m}55 m but has a displacement of 25 m25\ \text{m}25 m east.
Exam technique
  1. Do not assume distance and displacement are always equal: distance follows the actual route, displacement is the straight line from start to finish.
  2. A displacement answer is incomplete with only a magnitude; always give the direction.
  3. Returning to the start gives zero displacement, not zero distance.
  4. Match the command word: for distance, give the full route length with no direction; for displacement, give the straight-line change with magnitude and direction.
  5. In a comparison, use the terms scalar and vector: distance is a scalar, displacement is a vector.
Self review
  1. Define distance.
  2. Why is distance a scalar?
  3. What two things must a displacement include?
  4. What is the displacement of an object that finishes at its start point?
  5. Can an object’s distance be greater than the magnitude of its displacement?
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When motion happens along one line, first identify the start point and the finish point. A reference point is a fixed place you use to describe position, such as the school gate.

Distance is how far an object travels along its route. Displacement is the straight-line change from start to finish, and it must include direction.

If the route bends or doubles back, distance and displacement can be different. Both are usually measured in metres, symbol mmm.

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Distance is the [     ] of the [     ].

5.6.1a Distance and displacement Revision Guide

  1. GCSE
  2. /Physics
  3. /5.6.1a Distance and displacement

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