An electric drill is designed to rotate a drill bit. During one use, 1500 J of energy is transferred electrically to the drill. Of this energy, 600 J is dissipated by heating the drill and the surroundings. All the remaining energy is transferred usefully to the kinetic store of the rotating drill bit.
What calculation gives the percentage efficiency of the drill?
(1500 J - 600 J) / 1500 J x 100%
(1500 J - 600 J) / 600 J x 100%
600 J / 1500 J x 100%
1500 J / (1500 J - 600 J) x 100%
104 exam-style questions on AQA GCSE Physics 1.2 Conservation and dissipation of energy, covering 1.2.1 Energy transfers in a system and 1.2.2 Efficiency. Each one has a worked solution and a mark scheme showing where the marks go.