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Question 59
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Given that
x−1:2x−3=x+2:3x−2 x - 1 : 2x - 3 = x + 2 : 3x - 2
x
−
1
:
2
x
−
3
=
x
+
2
:
3
x
−
2
Find the possible values of
xx
x
.
[4]
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Algebraic Fractions Questions
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