Write x2+5x−243x2−7x−6\displaystyle \frac{x^2 + 5x - 24}{3x^2 - 7x - 6}3x2−7x−6x2+5x−24 in the form x+abx+c\displaystyle \frac{x + a}{bx + c}bx+cx+a where aaa, bbb, and c c\,c are integers.
Hence solve
x2+5x−243x2−7x−6=2 \frac{x^2 + 5x - 24}{3x^2 - 7x - 6}=2 3x2−7x−6x2+5x−24=2255 exam-style questions on WJEC GCSE Maths Algebraic Fractions. Each one has a worked solution and a mark scheme showing where the marks go.