m=54.8 g correct to 1 decimal place
m = 54.8 \text{ g correct to 1 decimal place}
m=54.8 g correct to 1 decimal placeV=6.24 cm3 correct to 3 significant figures
V = 6.24 \text{ cm}^3 \text{ correct to 3 significant figures}
V=6.24 cm3 correct to 3 significant figuresD=mV
D = \frac{m}{V}
D=Vm
DDD = density, mmm = mass, VVV = volume
By considering bounds, work out the value of D D\,D to a suitable degree of accuracy.
Give a reason for your answer.
