V=12.48 V correct to 2 decimal places
V = 12.48 \text{ V correct to 2 decimal places}
V=12.48 V correct to 2 decimal placesI=3.12 A correct to 3 significant figures
I = 3.12 \text{ A correct to 3 significant figures}
I=3.12 A correct to 3 significant figuresI=VR
I = \frac{V}{R}
I=RV
III = current, VVV = voltage, RRR = resistance
By considering bounds, work out the value of R R\,R to a suitable degree of accuracy.
Give a reason for your answer.
