32:I[196793,["/_next/static/chunks/0g36cb-mcivw7.js?dpl=nogit-1790701396","/_next/static/chunks/0z347qy8pf1j3.js?dpl=nogit-1790701396","/_next/static/chunks/2zbd126_oyq__.js?dpl=nogit-1790701396","/_next/static/chunks/1ew75_i487l-5.js?dpl=nogit-1790701396","/_next/static/chunks/15le0xz0fig32.js?dpl=nogit-1790701396","/_next/static/chunks/0u008gt6051u7.js?dpl=nogit-1790701396","/_next/static/chunks/2epfhfe5im7r6.js?dpl=nogit-1790701396","/_next/static/chunks/3ht89vb0p09bm.js?dpl=nogit-1790701396","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1790701396","/_next/static/chunks/2hyw6fyf3iqeh.js?dpl=nogit-1790701396","/_next/static/chunks/1bsq1mchpwo6z.js?dpl=nogit-1790701396","/_next/static/chunks/3r5hh4t0jf4es.js?dpl=nogit-1790701396","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1790701396","/_next/static/chunks/1h4wccj42vygd.js?dpl=nogit-1790701396","/_next/static/chunks/1odwrcl12kfnl.js?dpl=nogit-1790701396","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1790701396","/_next/static/chunks/2bsb8adax1pdp.js?dpl=nogit-1790701396","/_next/static/chunks/3ocoqwe4aht_u.js?dpl=nogit-1790701396","/_next/static/chunks/2u46tugibrk1v.js?dpl=nogit-1790701396","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1790701396","/_next/static/chunks/3ao1re0xmmur_.js?dpl=nogit-1790701396","/_next/static/chunks/3xa2z7fbv2riw.js?dpl=nogit-1790701396","/_next/static/chunks/3_lt5xft2vli-.js?dpl=nogit-1790701396","/_next/static/chunks/309o1kfcg2jbm.js?dpl=nogit-1790701396","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1790701396","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1790701396","/_next/static/chunks/3t0ml5lpxv0ny.js?dpl=nogit-1790701396","/_next/static/chunks/1x_yxljsdq0vl.js?dpl=nogit-1790701396","/_next/static/chunks/1coblm1-go81_.js?dpl=nogit-1790701396","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1790701396","/_next/static/chunks/01yo0wxu33311.js?dpl=nogit-1790701396","/_next/static/chunks/1xkpwfqqdrdio.js?dpl=nogit-1790701396","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1790701396","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1790701396","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1790701396","/_next/static/chunks/00ttxm70xm75x.js?dpl=nogit-1790701396","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1790701396","/_next/static/chunks/375u4k1enjdjk.js?dpl=nogit-1790701396","/_next/static/chunks/1ne0r03ukksa5.js?dpl=nogit-1790701396","/_next/static/chunks/075i0tnxt4not.js?dpl=nogit-1790701396","/_next/static/chunks/14e8hzq02amxs.js?dpl=nogit-1790701396","/_next/static/chunks/2job6vzx9q1be.js?dpl=nogit-1790701396","/_next/static/chunks/0o727iel7-n4q.js?dpl=nogit-1790701396","/_next/static/chunks/1r90gnkk5yun0.js?dpl=nogit-1790701396","/_next/static/chunks/0i4zom-kyjeci.js?dpl=nogit-1790701396","/_next/static/chunks/27300xkio5zct.js?dpl=nogit-1790701396","/_next/static/chunks/0m6ugdwrai1f_.js?dpl=nogit-1790701396","/_next/static/chunks/2opkuzmjw8cxb.js?dpl=nogit-1790701396","/_next/static/chunks/181u0pe6-1__x.js?dpl=nogit-1790701396","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1790701396","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1790701396","/_next/static/chunks/0f-6p5pag2tjw.js?dpl=nogit-1790701396","/_next/static/chunks/3-zx6jlroq8f_.js?dpl=nogit-1790701396","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1790701396","/_next/static/chunks/2olvbq0sf9-5z.js?dpl=nogit-1790701396","/_next/static/chunks/27wr6uo36_o7k.js?dpl=nogit-1790701396","/_next/static/chunks/2tom8_rk-gmeh.js?dpl=nogit-1790701396","/_next/static/chunks/3wqp-h5xnebw9.js?dpl=nogit-1790701396","/_next/static/chunks/0tx4q2z17aqku.js?dpl=nogit-1790701396","/_next/static/chunks/237j9p1936g2m.js?dpl=nogit-1790701396","/_next/static/chunks/1gtlwpzgzi12z.js?dpl=nogit-1790701396","/_next/static/chunks/2y341-r8ncizo.js?dpl=nogit-1790701396","/_next/static/chunks/2pacrnw1w83ax.js?dpl=nogit-1790701396"],"Gingerbread"] 34:I[647935,["/_next/static/chunks/0g36cb-mcivw7.js?dpl=nogit-1790701396","/_next/static/chunks/0z347qy8pf1j3.js?dpl=nogit-1790701396","/_next/static/chunks/2zbd126_oyq__.js?dpl=nogit-1790701396","/_next/static/chunks/1ew75_i487l-5.js?dpl=nogit-1790701396","/_next/static/chunks/15le0xz0fig32.js?dpl=nogit-1790701396","/_next/static/chunks/0u008gt6051u7.js?dpl=nogit-1790701396","/_next/static/chunks/2epfhfe5im7r6.js?dpl=nogit-1790701396","/_next/static/chunks/3ht89vb0p09bm.js?dpl=nogit-1790701396","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1790701396","/_next/static/chunks/2hyw6fyf3iqeh.js?dpl=nogit-1790701396","/_next/static/chunks/1bsq1mchpwo6z.js?dpl=nogit-1790701396","/_next/static/chunks/3r5hh4t0jf4es.js?dpl=nogit-1790701396","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1790701396","/_next/static/chunks/1h4wccj42vygd.js?dpl=nogit-1790701396","/_next/static/chunks/1odwrcl12kfnl.js?dpl=nogit-1790701396","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1790701396","/_next/static/chunks/2bsb8adax1pdp.js?dpl=nogit-1790701396","/_next/static/chunks/3ocoqwe4aht_u.js?dpl=nogit-1790701396","/_next/static/chunks/2u46tugibrk1v.js?dpl=nogit-1790701396","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1790701396","/_next/static/chunks/3ao1re0xmmur_.js?dpl=nogit-1790701396","/_next/static/chunks/3xa2z7fbv2riw.js?dpl=nogit-1790701396","/_next/static/chunks/3_lt5xft2vli-.js?dpl=nogit-1790701396","/_next/static/chunks/309o1kfcg2jbm.js?dpl=nogit-1790701396","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1790701396","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1790701396","/_next/static/chunks/3t0ml5lpxv0ny.js?dpl=nogit-1790701396","/_next/static/chunks/1x_yxljsdq0vl.js?dpl=nogit-1790701396","/_next/static/chunks/1coblm1-go81_.js?dpl=nogit-1790701396","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1790701396","/_next/static/chunks/01yo0wxu33311.js?dpl=nogit-1790701396","/_next/static/chunks/1xkpwfqqdrdio.js?dpl=nogit-1790701396","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1790701396","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1790701396","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1790701396","/_next/static/chunks/00ttxm70xm75x.js?dpl=nogit-1790701396","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1790701396","/_next/static/chunks/375u4k1enjdjk.js?dpl=nogit-1790701396","/_next/static/chunks/1ne0r03ukksa5.js?dpl=nogit-1790701396","/_next/static/chunks/075i0tnxt4not.js?dpl=nogit-1790701396","/_next/static/chunks/14e8hzq02amxs.js?dpl=nogit-1790701396","/_next/static/chunks/2job6vzx9q1be.js?dpl=nogit-1790701396","/_next/static/chunks/0o727iel7-n4q.js?dpl=nogit-1790701396","/_next/static/chunks/1r90gnkk5yun0.js?dpl=nogit-1790701396","/_next/static/chunks/0i4zom-kyjeci.js?dpl=nogit-1790701396","/_next/static/chunks/27300xkio5zct.js?dpl=nogit-1790701396","/_next/static/chunks/0m6ugdwrai1f_.js?dpl=nogit-1790701396","/_next/static/chunks/2opkuzmjw8cxb.js?dpl=nogit-1790701396","/_next/static/chunks/181u0pe6-1__x.js?dpl=nogit-1790701396","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1790701396","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1790701396","/_next/static/chunks/0f-6p5pag2tjw.js?dpl=nogit-1790701396","/_next/static/chunks/3-zx6jlroq8f_.js?dpl=nogit-1790701396","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1790701396","/_next/static/chunks/2olvbq0sf9-5z.js?dpl=nogit-1790701396","/_next/static/chunks/27wr6uo36_o7k.js?dpl=nogit-1790701396","/_next/static/chunks/2tom8_rk-gmeh.js?dpl=nogit-1790701396","/_next/static/chunks/3wqp-h5xnebw9.js?dpl=nogit-1790701396","/_next/static/chunks/0tx4q2z17aqku.js?dpl=nogit-1790701396","/_next/static/chunks/237j9p1936g2m.js?dpl=nogit-1790701396","/_next/static/chunks/1gtlwpzgzi12z.js?dpl=nogit-1790701396","/_next/static/chunks/2y341-r8ncizo.js?dpl=nogit-1790701396","/_next/static/chunks/2pacrnw1w83ax.js?dpl=nogit-1790701396"],"RecordResourceResume"] 35:I[830476,["/_next/static/chunks/0g36cb-mcivw7.js?dpl=nogit-1790701396","/_next/static/chunks/0z347qy8pf1j3.js?dpl=nogit-1790701396","/_next/static/chunks/2zbd126_oyq__.js?dpl=nogit-1790701396","/_next/static/chunks/1ew75_i487l-5.js?dpl=nogit-1790701396","/_next/static/chunks/15le0xz0fig32.js?dpl=nogit-1790701396","/_next/static/chunks/0u008gt6051u7.js?dpl=nogit-1790701396","/_next/static/chunks/2epfhfe5im7r6.js?dpl=nogit-1790701396","/_next/static/chunks/3ht89vb0p09bm.js?dpl=nogit-1790701396","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1790701396","/_next/static/chunks/2hyw6fyf3iqeh.js?dpl=nogit-1790701396","/_next/static/chunks/1bsq1mchpwo6z.js?dpl=nogit-1790701396","/_next/static/chunks/3r5hh4t0jf4es.js?dpl=nogit-1790701396","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1790701396","/_next/static/chunks/1h4wccj42vygd.js?dpl=nogit-1790701396","/_next/static/chunks/1odwrcl12kfnl.js?dpl=nogit-1790701396","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1790701396","/_next/static/chunks/2bsb8adax1pdp.js?dpl=nogit-1790701396","/_next/static/chunks/3ocoqwe4aht_u.js?dpl=nogit-1790701396","/_next/static/chunks/2u46tugibrk1v.js?dpl=nogit-1790701396","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1790701396","/_next/static/chunks/3ao1re0xmmur_.js?dpl=nogit-1790701396","/_next/static/chunks/3xa2z7fbv2riw.js?dpl=nogit-1790701396","/_next/static/chunks/3_lt5xft2vli-.js?dpl=nogit-1790701396","/_next/static/chunks/309o1kfcg2jbm.js?dpl=nogit-1790701396","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1790701396","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1790701396","/_next/static/chunks/3t0ml5lpxv0ny.js?dpl=nogit-1790701396","/_next/static/chunks/1x_yxljsdq0vl.js?dpl=nogit-1790701396","/_next/static/chunks/1coblm1-go81_.js?dpl=nogit-1790701396","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1790701396","/_next/static/chunks/01yo0wxu33311.js?dpl=nogit-1790701396","/_next/static/chunks/1xkpwfqqdrdio.js?dpl=nogit-1790701396","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1790701396","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1790701396","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1790701396","/_next/static/chunks/00ttxm70xm75x.js?dpl=nogit-1790701396","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1790701396","/_next/static/chunks/375u4k1enjdjk.js?dpl=nogit-1790701396","/_next/static/chunks/1ne0r03ukksa5.js?dpl=nogit-1790701396","/_next/static/chunks/075i0tnxt4not.js?dpl=nogit-1790701396","/_next/static/chunks/14e8hzq02amxs.js?dpl=nogit-1790701396","/_next/static/chunks/2job6vzx9q1be.js?dpl=nogit-1790701396","/_next/static/chunks/0o727iel7-n4q.js?dpl=nogit-1790701396","/_next/static/chunks/1r90gnkk5yun0.js?dpl=nogit-1790701396","/_next/static/chunks/0i4zom-kyjeci.js?dpl=nogit-1790701396","/_next/static/chunks/27300xkio5zct.js?dpl=nogit-1790701396","/_next/static/chunks/0m6ugdwrai1f_.js?dpl=nogit-1790701396","/_next/static/chunks/2opkuzmjw8cxb.js?dpl=nogit-1790701396","/_next/static/chunks/181u0pe6-1__x.js?dpl=nogit-1790701396","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1790701396","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1790701396","/_next/static/chunks/0f-6p5pag2tjw.js?dpl=nogit-1790701396","/_next/static/chunks/3-zx6jlroq8f_.js?dpl=nogit-1790701396","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1790701396","/_next/static/chunks/2olvbq0sf9-5z.js?dpl=nogit-1790701396","/_next/static/chunks/27wr6uo36_o7k.js?dpl=nogit-1790701396","/_next/static/chunks/2tom8_rk-gmeh.js?dpl=nogit-1790701396","/_next/static/chunks/3wqp-h5xnebw9.js?dpl=nogit-1790701396","/_next/static/chunks/0tx4q2z17aqku.js?dpl=nogit-1790701396","/_next/static/chunks/237j9p1936g2m.js?dpl=nogit-1790701396","/_next/static/chunks/1gtlwpzgzi12z.js?dpl=nogit-1790701396","/_next/static/chunks/2y341-r8ncizo.js?dpl=nogit-1790701396","/_next/static/chunks/2pacrnw1w83ax.js?dpl=nogit-1790701396"],"FlashcardAccessBranch"] 36:I[315438,["/_next/static/chunks/0g36cb-mcivw7.js?dpl=nogit-1790701396","/_next/static/chunks/0z347qy8pf1j3.js?dpl=nogit-1790701396","/_next/static/chunks/2zbd126_oyq__.js?dpl=nogit-1790701396","/_next/static/chunks/1ew75_i487l-5.js?dpl=nogit-1790701396","/_next/static/chunks/15le0xz0fig32.js?dpl=nogit-1790701396","/_next/static/chunks/0u008gt6051u7.js?dpl=nogit-1790701396","/_next/static/chunks/2epfhfe5im7r6.js?dpl=nogit-1790701396","/_next/static/chunks/3ht89vb0p09bm.js?dpl=nogit-1790701396","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1790701396","/_next/static/chunks/2hyw6fyf3iqeh.js?dpl=nogit-1790701396","/_next/static/chunks/1bsq1mchpwo6z.js?dpl=nogit-1790701396","/_next/static/chunks/3r5hh4t0jf4es.js?dpl=nogit-1790701396","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1790701396","/_next/static/chunks/1h4wccj42vygd.js?dpl=nogit-1790701396","/_next/static/chunks/1odwrcl12kfnl.js?dpl=nogit-1790701396","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1790701396","/_next/static/chunks/2bsb8adax1pdp.js?dpl=nogit-1790701396","/_next/static/chunks/3ocoqwe4aht_u.js?dpl=nogit-1790701396","/_next/static/chunks/2u46tugibrk1v.js?dpl=nogit-1790701396","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1790701396","/_next/static/chunks/3ao1re0xmmur_.js?dpl=nogit-1790701396","/_next/static/chunks/3xa2z7fbv2riw.js?dpl=nogit-1790701396","/_next/static/chunks/3_lt5xft2vli-.js?dpl=nogit-1790701396","/_next/static/chunks/309o1kfcg2jbm.js?dpl=nogit-1790701396","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1790701396","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1790701396","/_next/static/chunks/3t0ml5lpxv0ny.js?dpl=nogit-1790701396","/_next/static/chunks/1x_yxljsdq0vl.js?dpl=nogit-1790701396","/_next/static/chunks/1coblm1-go81_.js?dpl=nogit-1790701396","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1790701396","/_next/static/chunks/01yo0wxu33311.js?dpl=nogit-1790701396","/_next/static/chunks/1xkpwfqqdrdio.js?dpl=nogit-1790701396","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1790701396","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1790701396","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1790701396","/_next/static/chunks/00ttxm70xm75x.js?dpl=nogit-1790701396","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1790701396","/_next/static/chunks/375u4k1enjdjk.js?dpl=nogit-1790701396","/_next/static/chunks/1ne0r03ukksa5.js?dpl=nogit-1790701396","/_next/static/chunks/075i0tnxt4not.js?dpl=nogit-1790701396","/_next/static/chunks/14e8hzq02amxs.js?dpl=nogit-1790701396","/_next/static/chunks/2job6vzx9q1be.js?dpl=nogit-1790701396","/_next/static/chunks/0o727iel7-n4q.js?dpl=nogit-1790701396","/_next/static/chunks/1r90gnkk5yun0.js?dpl=nogit-1790701396","/_next/static/chunks/0i4zom-kyjeci.js?dpl=nogit-1790701396","/_next/static/chunks/27300xkio5zct.js?dpl=nogit-1790701396","/_next/static/chunks/0m6ugdwrai1f_.js?dpl=nogit-1790701396","/_next/static/chunks/2opkuzmjw8cxb.js?dpl=nogit-1790701396","/_next/static/chunks/181u0pe6-1__x.js?dpl=nogit-1790701396","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1790701396","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1790701396","/_next/static/chunks/0f-6p5pag2tjw.js?dpl=nogit-1790701396","/_next/static/chunks/3-zx6jlroq8f_.js?dpl=nogit-1790701396","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1790701396","/_next/static/chunks/2olvbq0sf9-5z.js?dpl=nogit-1790701396","/_next/static/chunks/27wr6uo36_o7k.js?dpl=nogit-1790701396","/_next/static/chunks/2tom8_rk-gmeh.js?dpl=nogit-1790701396","/_next/static/chunks/3wqp-h5xnebw9.js?dpl=nogit-1790701396","/_next/static/chunks/0tx4q2z17aqku.js?dpl=nogit-1790701396","/_next/static/chunks/237j9p1936g2m.js?dpl=nogit-1790701396","/_next/static/chunks/1gtlwpzgzi12z.js?dpl=nogit-1790701396","/_next/static/chunks/2y341-r8ncizo.js?dpl=nogit-1790701396","/_next/static/chunks/2pacrnw1w83ax.js?dpl=nogit-1790701396"],"TopicFlashcardRunner"] 23:[["$","$L32",null,{"feature":"flashcards"}],"$L33",["$","$L34",null,{"href":"/gcse/maths/wjec/grade-7-7-2-bounds/flashcards","label":"Bounds","subjectCode":"gcse_maths__wjec","surface":"flashcards"}],["$","$L35",null,{"runner":["$","div",null,{"className":"min-h-0 flex-1 overflow-hidden bg-background","children":["$","$L36",null,{"decks":[{"id":"58b63771-5ff1-b5fd-8d0e-7366d04adfa1","title":"Bounds Flashcards","topicId":"4feac0e1-b513-71ba-3e62-77beec7a871f","topicSlug":"grade-7-7-2-bounds","cards":[{"id":"cb314a29-d6bf-25c3-3b64-34fab5223da4","cardType":"cloze","points":null,"front":"The lower bound is the [ ] possible value before rounding, while the upper bound is the largest boundary value.","back":"The lower bound is the smallest possible value before rounding, while the upper bound is the largest boundary value.","mcqOptions":[{"text":"smallest","correct":true,"explanation":"The lower bound marks the smallest possible original value within the interval of values that round to the stated measurement."},{"text":"largest","correct":false,"explanation":"This reverses the definitions of the two bounds. The lower bound is the smallest possible original value that could have produced the stated rounded value."},{"text":"average","correct":false,"explanation":"A bound is an endpoint, not a mean of the possible values. The lower bound is the smallest possible value before rounding."},{"text":"nearest","correct":false,"explanation":"This confuses a boundary with the rounded value itself. The lower bound is the smallest possible value in the rounding interval."}]},{"id":"052c994b-639a-f6b7-8ed0-a0fc371b7a51","cardType":"cloze","points":null,"front":"The lower bound is the smallest possible value before rounding, while the upper bound is the [ ] boundary value.","back":"The lower bound is the smallest possible value before rounding, while the upper bound is the largest boundary value.","mcqOptions":[{"text":"largest","correct":true,"explanation":"The upper bound marks the largest boundary value of the interval containing all original values that round to the stated measurement."},{"text":"smallest","correct":false,"explanation":"This describes the lower boundary rather than the upper boundary. The upper bound is the largest boundary value in the rounding interval."},{"text":"nearest","correct":false,"explanation":"The rounded value may be nearest to the original value, but the upper bound is specifically the largest boundary value permitted."},{"text":"central","correct":false,"explanation":"The centre of the interval is the rounded value, not its upper boundary. The upper bound is the largest boundary value."}]},{"id":"25898e8d-5f61-28d0-c114-9492e4f62278","cardType":"basic","points":1,"front":"What is the half-gap for a measurement rounded to the nearest $5\\text{ m}$?","back":"$$2.5\\text{ m}$","mcqOptions":[{"text":"$$2.5\\text{ m}$","correct":true,"explanation":"Values rounded to the nearest $5\\text{ m}$ have a rounding gap of $5\\text{ m}$, so the half-gap is $5 \\div 2 = 2.5\\text{ m}$."},{"text":"$$1.25\\text{ m}$","correct":false,"explanation":"This uses one quarter of the rounding interval rather than one half. Half of the $5\\text{ m}$ gap is $2.5\\text{ m}$."},{"text":"$$5\\text{ m}$","correct":false,"explanation":"This uses the full rounding gap instead of halving it. The half-gap for rounding to the nearest $5\\text{ m}$ is $2.5\\text{ m}$."},{"text":"$$10\\text{ m}$","correct":false,"explanation":"This incorrectly doubles the rounding gap. The gap is $5\\text{ m}$ and its half-gap is therefore $2.5\\text{ m}$."}]},{"id":"03a10a62-c07b-a616-08da-c19704b4ad71","cardType":"basic","points":1,"front":"What is the half-gap for a measurement rounded correct to $2$ decimal places?","back":"$$0.005$","mcqOptions":[{"text":"$$0.005$","correct":true,"explanation":"Two decimal places correspond to a rounding increment of $0.01$. The half-gap is therefore $0.01 \\div 2 = 0.005$."},{"text":"$$0.01$","correct":false,"explanation":"This is the full gap between consecutive values to two decimal places. Halving $0.01$ gives the required half-gap of $0.005$."},{"text":"$$0.05$","correct":false,"explanation":"This is the half-gap for rounding to one decimal place. For two decimal places, the gap is $0.01$, giving a half-gap of $0.005$."},{"text":"$$0.0005$","correct":false,"explanation":"This introduces an extra decimal place when halving. Half of the two-decimal-place increment $0.01$ is $0.005$, not $0.0005$."}]},{"id":"44cf0208-6046-8d69-7726-1e281725c6ba","cardType":"basic","points":1,"front":"If a measurement in $\\text{cm}$ is rounded to the nearest $\\text{mm}$, what half-gap value is used?","back":"$$0.05\\text{ cm}$","mcqOptions":[{"text":"$$0.05\\text{ cm}$","correct":true,"explanation":"One millimetre equals $0.1\\text{ cm}$, so rounding to the nearest millimetre gives a half-gap of $0.1 \\div 2 = 0.05\\text{ cm}$."},{"text":"$$0.1\\text{ cm}$","correct":false,"explanation":"This uses the full $1\\text{ mm}$ rounding gap, converted to centimetres, without halving it. The required half-gap is $0.05\\text{ cm}$."},{"text":"$$0.5\\text{ cm}$","correct":false,"explanation":"This incorrectly treats half a millimetre as half a centimetre. Since $0.5\\text{ mm}=0.05\\text{ cm}$, the half-gap is $0.05\\text{ cm}$."},{"text":"$$0.005\\text{ cm}$","correct":false,"explanation":"This divides by ten once too many during the unit conversion. Half a millimetre is $0.05\\text{ cm}$, not $0.005\\text{ cm}$."}]},{"id":"118ee199-8256-e8c3-77a2-65f527b463f0","cardType":"cloze","points":null,"front":"A rounded value $l$ is expressed as an interval using the symbols: $\\text{[...]} l < <$.","back":"A rounded value $l$ is expressed as an interval using the symbols: $\\boxed{\\le} l < <$.","mcqOptions":[{"text":"$$\\le$","correct":true,"explanation":"The lower boundary is included in a bounds interval, so the lower bound is less than or equal to the value: $\\text{lower bound} \\le l$."},{"text":"$$<$","correct":false,"explanation":"Using a strict inequality would exclude the lower boundary. Bounds intervals include the lower bound, so the left-hand comparison must use $\\le$."},{"text":"$$\\ge$","correct":false,"explanation":"This reverses the direction of the comparison. The interval is written from the lower bound to $l$, so the required symbol is $\\le$."},{"text":"$$>$","correct":false,"explanation":"This both reverses the comparison and excludes the lower boundary. The correct relationship is $\\text{lower bound} \\le l$."}]},{"id":"b22d5261-4fa0-d25f-8f65-338d5ea90224","cardType":"cloze","points":null,"front":"A rounded value $l$ is expressed as an interval using the symbols: $\\le l < \\text{[...]}$.","back":"A rounded value $l$ is expressed as an interval using the symbols: $\\le l < \\boxed{<}$.","mcqOptions":[{"text":"$$<$","correct":true,"explanation":"The upper boundary is excluded from the interval, so the value must be strictly less than the upper bound. This requires the symbol $<$."},{"text":"$$\\le$","correct":false,"explanation":"The upper boundary is not included because values exactly at it round to the next value. The right-hand comparison must therefore use $<$."},{"text":"$$>$","correct":false,"explanation":"This reverses the comparison, suggesting that $l$ exceeds the upper bound. Instead, $l$ must be strictly less than the upper bound, using $<$."},{"text":"$$\\ge$","correct":false,"explanation":"This reverses the comparison and incorrectly includes the upper boundary. The value must be strictly less than the upper bound, so the correct symbol is $<$."}]},{"id":"322853a0-9d4c-b8e5-f17a-a32d42c5b116","cardType":"basic","points":1,"front":"How do you calculate the upper bound for the area of a rectangle?","back":"$$\\text{upper length} \\times \\text{upper width}$","mcqOptions":[{"text":"$$\\text{upper length} \\times \\text{upper width}$","correct":true,"explanation":"For positive rectangle dimensions, the area increases as either dimension increases. Its upper bound is therefore found by multiplying both upper bounds."},{"text":"$$\\text{lower length} \\times \\text{lower width}$","correct":false,"explanation":"Using both lower dimensions gives the lower bound for the area, not the upper bound. The maximum area uses the upper length and upper width."},{"text":"$$\\text{upper length} \\times \\text{lower width}$","correct":false,"explanation":"Using the lower width prevents the area from being as large as possible. The upper bound requires both the upper length and upper width."},{"text":"$$\\text{lower length} \\times \\text{upper width}$","correct":false,"explanation":"Using the lower length prevents the area from being maximised. Both dimensions must take their upper bounds to find the upper bound for area."}]},{"id":"a637a219-6b14-ad43-a268-b2103d5e0e80","cardType":"basic","points":2,"front":"How do you calculate the lower bound for the perimeter of a rectangle?","back":"$$2 \\times (\\text{lower length} + \\text{lower width})$","mcqOptions":[{"text":"$$2 \\times (\\text{lower length} + \\text{lower width})$","correct":true,"explanation":"The perimeter increases as either dimension increases, so using both lower bounds gives the smallest possible perimeter: twice the sum of the lower length and lower width."},{"text":"$$2 \\times (\\text{upper length} + \\text{upper width})$","correct":false,"explanation":"Using both upper bounds gives the upper bound, not the lower bound, of the perimeter. The lower bound is $2 \\times (\\text{lower length} + \\text{lower width})$."},{"text":"$$2 \\times (\\text{lower length} + \\text{upper width})$","correct":false,"explanation":"Mixing a lower length with an upper width does not produce the smallest possible perimeter. Both dimensions must use their lower bounds in the perimeter formula."},{"text":"$$2 \\times (\\text{upper length} + \\text{lower width})$","correct":false,"explanation":"Using the upper length makes the calculated perimeter larger than its minimum possible value. The lower bounds of both the length and width are required."}]},{"id":"d351da8f-f7ab-38f1-0155-b2712e82a999","cardType":"basic","points":1,"front":"To find the lower bound for a circle's circumference ($C=2\\pi r$), which bound of the radius is required?","back":"The lower bound of the radius.","mcqOptions":[{"text":"The lower bound of the radius.","correct":true,"explanation":"Circumference is directly proportional to radius because $C=2\\pi r$. Therefore, the smallest possible radius produces the lower bound of the circumference."},{"text":"The upper bound of the radius.","correct":false,"explanation":"Using the upper radius produces the upper bound of the circumference because circumference increases with radius. The lower bound of the radius is required for the lower circumference bound."},{"text":"The rounded value of the radius.","correct":false,"explanation":"The rounded radius is not the smallest possible radius and therefore cannot guarantee the lower circumference bound. Use the lower bound of the radius in $C=2\\pi r$."},{"text":"The midpoint value of the radius.","correct":false,"explanation":"The midpoint lies between the radius bounds, so it gives neither an upper nor a lower circumference bound. The lower radius bound gives the lower circumference bound."}]},{"id":"e7e384a3-f3b9-85df-5abb-db7650fe1dbc","cardType":"basic","points":1,"front":"How do you calculate the upper bound of a product $v = x \\times y$?","back":"$$\\text{upper } x \\times \\text{upper } y$","mcqOptions":[{"text":"$$\\text{upper } x \\times \\text{upper } y$","correct":true,"explanation":"For positive quantities, a product is greatest when both factors take their greatest possible values. Therefore, multiply the upper bound of $x$ by the upper bound of $y$."},{"text":"$$\\text{lower } x \\times \\text{lower } y$","correct":false,"explanation":"Using both lower bounds gives the lower bound of the product for positive quantities. The upper product bound requires $\\text{upper } x \\times \\text{upper } y$."},{"text":"$$\\text{upper } x \\times \\text{lower } y$","correct":false,"explanation":"Mixing an upper bound with a lower bound does not maximise both positive factors. The largest possible product is found by multiplying both upper bounds."},{"text":"$$\\text{lower } x \\times \\text{upper } y$","correct":false,"explanation":"Using the lower bound of $x$ prevents the product from reaching its greatest possible value. For the upper bound, multiply the upper bounds of both variables."}]},{"id":"aa6e60d2-d43d-edd5-2c95-cad820fedcd9","cardType":"cloze","points":null,"front":"To find the upper bound of a fraction, use the [ ] numerator and the lower denominator.","back":"To find the upper bound of a fraction, use the upper numerator and the lower denominator.","mcqOptions":[{"text":"upper","correct":true,"explanation":"A fraction becomes larger when its positive numerator increases. Therefore, its upper bound uses the upper numerator together with the lower denominator."},{"text":"lower","correct":false,"explanation":"Using the lower numerator tends to minimise rather than maximise a positive fraction. Its upper bound requires the upper numerator and the lower denominator."},{"text":"central","correct":false,"explanation":"A central numerator value does not represent an extreme and therefore cannot guarantee an upper bound. Use the upper numerator and lower denominator to maximise the fraction."},{"text":"rounded","correct":false,"explanation":"The rounded numerator is only an estimate and need not be the greatest possible value. The upper numerator must be used to obtain the fraction’s upper bound."}]},{"id":"6186b684-8599-44d4-4ca7-92a477c381c1","cardType":"cloze","points":null,"front":"To find the upper bound of a fraction, use the upper numerator and the [ ] denominator.","back":"To find the upper bound of a fraction, use the upper numerator and the lower denominator.","mcqOptions":[{"text":"lower","correct":true,"explanation":"For a positive fraction, decreasing the denominator increases the quotient. Therefore, the upper bound uses the lower denominator together with the upper numerator."},{"text":"upper","correct":false,"explanation":"Using the upper denominator makes a positive quotient smaller, so it contributes to a lower bound. The upper fraction bound requires the lower denominator."},{"text":"central","correct":false,"explanation":"A central denominator is not an extreme value and cannot guarantee the greatest possible quotient. The lower denominator must be paired with the upper numerator."},{"text":"rounded","correct":false,"explanation":"The rounded denominator is an estimate rather than the smallest possible value. To maximise the fraction, use the denominator’s lower bound."}]},{"id":"7560b83f-641c-59df-9e40-a8850e0b9577","cardType":"basic","points":2,"front":"In the formula $v = \\frac{s}{t}$, why is the lower bound of $t$ used to find the upper bound of $v$?","back":"A smaller denominator results in a larger overall quotient.","mcqOptions":[{"text":"A smaller denominator results in a larger overall quotient.","correct":true,"explanation":"With a fixed positive numerator, division by a smaller positive number gives a larger result. Thus, the lower bound of $t$ helps produce the upper bound of $v$."},{"text":"A larger denominator results in a larger overall quotient.","correct":false,"explanation":"This reverses the effect of the denominator: increasing a positive denominator decreases the quotient. The upper bound of $v$ therefore uses the lower bound of $t$."},{"text":"A smaller denominator results in a smaller overall quotient.","correct":false,"explanation":"This confuses division with direct proportion. For a fixed positive numerator, a smaller denominator gives a larger quotient, so the lower bound of $t$ is used."},{"text":"A larger denominator results in an unchanged overall quotient.","correct":false,"explanation":"Changing the denominator changes the quotient when the numerator is fixed. A smaller positive denominator creates a larger quotient, which is why the lower bound of $t$ is required."}]},{"id":"778d5db8-d27a-7b5d-2f66-9040abab24b8","cardType":"basic","points":2,"front":"To find the lower bound of a fraction, which bounds for the numerator and denominator are used?","back":"

Lower bound of the numerator
Upper bound of the denominator

","mcqOptions":[{"text":"

Lower bound of the numerator
Upper bound of the denominator

","correct":true,"explanation":"A positive fraction is minimised by making its numerator as small as possible and its denominator as large as possible. These bounds therefore give the lower quotient bound."},{"text":"

Upper bound of the numerator
Lower bound of the denominator

","correct":false,"explanation":"This combination maximises a positive fraction, so it gives the upper bound. The lower bound uses the lower numerator and the upper denominator."},{"text":"

Lower bound of the numerator
Lower bound of the denominator

","correct":false,"explanation":"Although the lower numerator reduces the fraction, the lower denominator increases it. To guarantee the smallest quotient, use the lower numerator and upper denominator."},{"text":"

Upper bound of the numerator
Upper bound of the denominator

","correct":false,"explanation":"The upper denominator reduces the fraction, but the upper numerator increases it, so this does not guarantee the minimum. Use the lower numerator and upper denominator."}]},{"id":"22a2cbee-4153-e1c8-19e5-77d9bfd765b6","cardType":"basic","points":1,"front":"To find the lower bound of the hypotenuse $c$ in $c^2 = a^2 + b^2$, which bounds of $a$ and $b$ are used?","back":"The lower bounds of both $a$ and $b$.","mcqOptions":[{"text":"The lower bounds of both $a$ and $b$.","correct":true,"explanation":"For positive lengths, increasing either shorter side increases $a^2+b^2$ and hence $c$. The lower hypotenuse bound therefore uses the lower bounds of both $a$ and $b$."},{"text":"The upper bounds of both $a$ and $b$.","correct":false,"explanation":"Using both upper bounds makes $a^2+b^2$ as large as possible, producing the upper bound of $c$. The lower bound requires both lower bounds."},{"text":"The lower bound of $a$ and upper bound of $b$.","correct":false,"explanation":"Using the upper bound of $b$ does not minimise $a^2+b^2$, so the result is not the lower hypotenuse bound. Both $a$ and $b$ require lower bounds."},{"text":"The upper bound of $a$ and lower bound of $b$.","correct":false,"explanation":"Using the upper bound of $a$ prevents $a^2+b^2$ from taking its smallest possible value. The lower bounds of both sides are needed."}]},{"id":"2c7ab50e-1a76-30c2-ea97-a01f894232d7","cardType":"basic","points":1,"front":"To find the lower bound of side $b = \\sqrt{c^2 - a^2}$, which bound of the hypotenuse $c$ is used?","back":"The lower bound of $c$.","mcqOptions":[{"text":"The lower bound of $c$.","correct":true,"explanation":"A smaller hypotenuse gives a smaller value of $c^2$, so it minimises $c^2-a^2$ and therefore produces the lower bound of $b$."},{"text":"The upper bound of $c$.","correct":false,"explanation":"Using the upper bound of $c$ increases $c^2$ and therefore increases $b$. The lower bound of $c$ is needed to minimise the result."},{"text":"The rounded value of $c$.","correct":false,"explanation":"The stated rounded value is not an extreme of the possible interval. The lower bound of $c$ must be used because it produces the smallest possible $c^2$."},{"text":"The midpoint value of $c$.","correct":false,"explanation":"The midpoint does not give the smallest possible result and is usually just the stated rounded value. The lower bound of $c$ is required to minimise $b$."}]},{"id":"8b455728-7745-5858-2693-5b90e5c9490e","cardType":"basic","points":2,"front":"To find the lower bound of side $b = \\sqrt{c^2 - a^2}$, which bound of side $a$ is used?","back":"The upper bound of $a$ (subtracting a larger value minimizes the result).","mcqOptions":[{"text":"The upper bound of $a$ (subtracting a larger value minimizes the result).","correct":true,"explanation":"Because $a^2$ is subtracted, its largest possible value makes $c^2-a^2$ as small as possible. This gives the lower bound of $b$."},{"text":"The lower bound of $a$ (subtracting a smaller value minimizes the result).","correct":false,"explanation":"Subtracting a smaller value actually leaves a larger result, so this would help maximise $b$. The upper bound of $a$ is used to find the lower bound."},{"text":"The rounded value of $a$ (subtracting the stated value minimizes the result).","correct":false,"explanation":"The rounded value is not the largest possible value of $a$, so it cannot guarantee the minimum. The upper bound of $a$ must be subtracted."},{"text":"The midpoint value of $a$ (subtracting the central value minimizes the result).","correct":false,"explanation":"Using the midpoint ignores the extreme values allowed by the bounds. Since $a^2$ is subtracted, its upper bound gives the smallest possible result."}]},{"id":"28fab97a-6eec-8329-9440-d643ea20fda0","cardType":"basic","points":1,"front":"Define a suitable degree of accuracy in the context of bounds.","back":"The rounding level where the lower bound and upper bound round to the same value.","mcqOptions":[{"text":"The rounding level where the lower bound and upper bound round to the same value.","correct":true,"explanation":"If both endpoints round to the same value at a particular accuracy, every possible value between them also rounds to that value, making the accuracy justified."},{"text":"The rounding level where the lower bound and upper bound round to different values.","correct":false,"explanation":"Different rounded endpoint values mean the interval does not determine one answer at that accuracy. A suitable accuracy is one where both bounds round to the same value."},{"text":"The rounding level where the lower bound and upper bound have the same digits.","correct":false,"explanation":"Bounds may share several digits without rounding to the same final value. Suitability depends specifically on both bounds rounding to exactly the same value."},{"text":"The rounding level where the lower bound and upper bound differ by the rounding unit.","correct":false,"explanation":"Comparing the interval width with the rounding unit is not sufficient, especially near a rounding boundary. Both bounds must round to the same value."}]},{"id":"04f95fea-9bad-0d1d-5878-fe22f4f1e656","cardType":"basic","points":2,"front":"If $LB = 5.359$ and $UB = 5.371$, why is \"2 decimal places\" NOT a suitable degree of accuracy?","back":"They round to different values ($5.36$ and $5.37$).","mcqOptions":[{"text":"They round to different values ($5.36$ and $5.37$).","correct":true,"explanation":"At two decimal places, $5.359$ rounds to $5.36$, while $5.371$ rounds to $5.37$. Therefore the interval does not guarantee one rounded answer."},{"text":"They round to the same value ($5.36$ and $5.36$).","correct":false,"explanation":"This incorrectly rounds $5.371$ down; its third decimal digit is $1$, so it rounds to $5.37$. The bounds therefore give different two-decimal-place values."},{"text":"They round to different values ($5.35$ and $5.38$).","correct":false,"explanation":"These results come from moving each endpoint outward rather than applying standard rounding. Correctly rounding gives $5.36$ and $5.37$, which are still different."},{"text":"They round to the same value ($5.37$ and $5.37$).","correct":false,"explanation":"This incorrectly rounds $5.359$ up to $5.37$; its hundredths rounding is determined by the third decimal digit, giving $5.36$. The endpoints round differently."}]},{"id":"72ad45ee-89c5-2564-7544-2d39b8fdc0bf","cardType":"basic","points":2,"front":"What are the bounds for $58.0\\text{ cm}$ correct to the nearest millimetre?","back":"$$57.95 \\le l < 58.05$","mcqOptions":[{"text":"$$57.95 \\le l < 58.05$","correct":true,"explanation":"One millimetre is $0.1$ cm, so the rounding interval extends half of this, $0.05$ cm, on either side of $58.0$ cm."},{"text":"$$57.5 \\le l < 58.5$","correct":false,"explanation":"These are the bounds for a measurement rounded to the nearest centimetre, not millimetre. Nearest millimetre means half of $0.1$ cm, giving $57.95 \\le l < 58.05$."},{"text":"$$57.9 \\le l < 58.1$","correct":false,"explanation":"This subtracts and adds a whole millimetre rather than half a millimetre. Rounding bounds use half the rounding unit, so the correct endpoints are $57.95$ and $58.05$."},{"text":"$$57.99 \\le l < 58.01$","correct":false,"explanation":"This interval uses $0.01$ cm on either side, equivalent to only $0.1$ mm. Half of the $1$ mm rounding unit is $0.5$ mm, or $0.05$ cm."}]},{"id":"bf1b9009-2926-84ea-603b-11e5a1cb4c1f","cardType":"cloze","points":null,"front":"When solving bounds problems, you should calculate the bounds for each value [ ] substituting them into a formula.","back":"When solving bounds problems, you should calculate the bounds for each value before substituting them into a formula.","mcqOptions":[{"text":"before","correct":true,"explanation":"Each measured quantity has its own interval of possible values. Finding those bounds before substitution ensures the correct extreme values are selected for the required result."},{"text":"after","correct":false,"explanation":"Substituting the rounded measurements first loses the extreme values needed for a bounds calculation. The lower and upper bounds of every value must be found before substitution."},{"text":"while","correct":false,"explanation":"Working out bounds during substitution encourages values to be bounded inconsistently or overlooked. Determine each quantity’s lower and upper bounds before applying the formula."},{"text":"without","correct":false,"explanation":"Bounds must eventually be substituted into the formula to calculate the result’s limits. They should be calculated before substitution, not used as a replacement for substitution."}]}]}],"examCountdown":{"examDate":"2027-05-14","paperLabel":"Unit 1"},"heading":"Bounds","title":"Bounds Flashcards","topbar":{"backHref":"/gcse/maths/wjec/flashcards"},"topicSidebar":"$L37"}]}],"topicId":"4feac0e1-b513-71ba-3e62-77beec7a871f","walled":"$L38"}],"$L39","$L3a"]