Surds

a.

Show that $112+2\displaystyle \frac{1}{\frac{1}{\sqrt{2}} + \sqrt{2}}$ can be written as $23\displaystyle \frac{\sqrt{2}}{3}$

[3]

b.

Hence find the exact value of $312+2\displaystyle \frac{3}{\frac{1}{\sqrt{2}} + \sqrt{2}}$

[1]

Surds

a.

Show that $112+2\displaystyle \frac{1}{\frac{1}{\sqrt{2}} + \sqrt{2}}$ can be written as $23\displaystyle \frac{\sqrt{2}}{3}$

[3]

b.

Hence find the exact value of $312+2\displaystyle \frac{3}{\frac{1}{\sqrt{2}} + \sqrt{2}}$

[1]

Surds

Surds Questions