Show that (3x−1)(4x+3)(x−9)=12x3−103x2−48x+27(3x - 1)(4x + 3)(x - 9) = 12x^3 - 103x^2 - 48x + 27(3x−1)(4x+3)(x−9)=12x3−103x2−48x+27 for all values of xxx.