Expanding Triple Brackets

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Question 48
Medium

Show that (2x+3)(5x+2)(x−5)=10x3−31x2−89x−30(2x + 3)(5x + 2)(x - 5) = 10x^3 - 31x^2 - 89x - 30(2x+3)(5x+2)(x−5)=10x3−31x2−89x−30 for all values of xxx.

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Expanding Triple Brackets Questions

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