Show that (2x+1)(3x−2)(x+4)=6x3+23x2−6x−8(2x + 1)(3x - 2)(x + 4) = 6x^3 + 23x^2 - 6x - 8(2x+1)(3x−2)(x+4)=6x3+23x2−6x−8 for all values of xxx.
