Expanding Triple Brackets

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Question 29
Medium

Show that (5x−1)(x−2)(3x+2)=15x3−23x2−16x+4(5x - 1)(x - 2)(3x + 2) = 15x^3 - 23x^2 - 16x + 4(5x−1)(x−2)(3x+2)=15x3−23x2−16x+4 for all values of xxx.

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Expanding Triple Brackets Questions

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