Show that (3x−2)(x+4)(2x−1)=6x3+17x2−26x+8(3x - 2)(x + 4)(2x - 1) = 6x^3 + 17x^2 - 26x + 8(3x−2)(x+4)(2x−1)=6x3+17x2−26x+8 for all values of xxx.