Show that (3x+2)(2x−1)(x+4)=6x3+25x2+2x−8(3x + 2)(2x - 1)(x + 4) = 6x^3 + 25x^2 + 2x - 8(3x+2)(2x−1)(x+4)=6x3+25x2+2x−8 for all values of xxx.