Exact trig values
What you'll learn
- What “exact” means in trigonometry.
- The exact values of sine, cosine and tangent for 0°, 30°, 45°, 60° and 90°.
- How to use special triangles to remember the values.
- How to use exact trig values to find missing lengths in right-angled triangles.
What does “exact” mean?
In this topic, you are not estimating with a calculator. You are giving the precise value.
Exact value
An exact value is an answer written without rounding. It might be a whole number, a fraction, or a surd, which is a square root that does not simplify to a whole number, such as 2\sqrt{2}2.
For example, 0.707 is only an approximation. The exact value of sin(45∘)\sin(45^\circ)sin(45∘) is 22\frac{\sqrt{2}}{2}22.
Exact, not rounded
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Suppose you are asked for sin(45∘)\sin(45^\circ)sin(45∘).
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A calculator gives a decimal starting 0.7071..., but this is rounded.
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The exact GCSE answer is:
sin(45∘)=22\sin(45^\circ)=\frac{\sqrt{2}}{2}sin(45∘)=22
Using decimals too early
If the question asks for an exact value, do not write a rounded decimal like 0.866. Use the fraction or surd form instead.
Right-angled triangle basics
Exact trig values come from special right-angled triangles.
The three side names
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The hypotenuse is the longest side of a right-angled triangle. It is opposite the right angle.
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The opposite side is opposite the angle you are using.
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The adjacent side is next to the angle you are using, but it is not the hypotenuse.

We often call the angle we are using θ\thetaθ, pronounced “theta”.
SOHCAHTOA
SOHCAHTOA reminds you that sinθ=oppositehypotenuse\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}sinθ=hypotenuseopposite, cosθ=adjacenthypotenuse\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}cosθ=hypotenuseadjacent and tanθ=oppositeadjacent\tan\theta=\frac{\text{opposite}}{\text{adjacent}}tanθ=adjacentopposite.
Choosing the correct trig ratio
- Imagine a right-angled triangle where the side opposite θ\thetaθ is 6 cm and the hypotenuse is 12 cm.

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Opposite and hypotenuse means use sine:
sinθ=oppositehypotenuse\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}sinθ=hypotenuseopposite -
Substitute the side lengths:
sinθ=612\sin\theta=\frac{6}{12}sinθ=126 -
Simplify:
sinθ=12\sin\theta=\frac{1}{2}sinθ=21
The 45° special triangle
An isosceles triangle has two equal sides. If you make an isosceles right-angled triangle, the two smaller angles are both 45°.
The useful side lengths are:

- two shorter sides: 1 and 1
- hypotenuse: 2\sqrt{2}2
So for a 45° angle, the opposite and adjacent sides are the same.
Finding an exact value at 45°
- Use the 45-45-90 triangle with shorter sides 1 and 1, and hypotenuse 2\sqrt{2}2.

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For sin(45∘)\sin(45^\circ)sin(45∘), use opposite over hypotenuse:
sin(45∘)=12\sin(45^\circ)=\frac{1}{\sqrt{2}}sin(45∘)=21 -
Remove the square root from the denominator:
12=22\frac{1}{\sqrt{2}}=\frac{\sqrt{2}}{2}21=22 -
Therefore:
sin(45∘)=22\sin(45^\circ)=\frac{\sqrt{2}}{2}sin(45∘)=22
45° shortcut
For 45°, sine and cosine are equal: sin(45∘)=cos(45∘)=22\sin(45^\circ)=\cos(45^\circ)=\frac{\sqrt{2}}{2}sin(45∘)=cos(45∘)=22.
The 30° and 60° special triangle
An equilateral triangle has all three sides equal and all three angles 60°. If you cut one in half, you get a 30-60-90 right-angled triangle.

The useful side lengths are:
- shortest side: 1
- middle side: 3\sqrt{3}3
- hypotenuse: 2
For the 30° angle, the opposite side is the shortest side.
For the 60° angle, the opposite side is the 3\sqrt{3}3 side.

Finding an exact value at 60°
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Use the 30-60-90 triangle with side lengths 1, 3\sqrt{3}3 and 2.
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For a 60° angle, the opposite side is 3\sqrt{3}3 and the adjacent side is 1.
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Tangent uses opposite over adjacent:
tan(60∘)=31\tan(60^\circ)=\frac{\sqrt{3}}{1}tan(60∘)=13 -
So tan(60∘)=3\tan(60^\circ)=\sqrt{3}tan(60∘)=3.
Swapping 30° and 60°
For sine, 30° has the smaller value 12\frac{1}{2}21 and 60° has the larger value 32\frac{\sqrt{3}}{2}23. Cosine is the other way round.
The exact values to know
Memorise these values
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0°: sin(0∘)=0\sin(0^\circ)=0sin(0∘)=0, cos(0∘)=1\cos(0^\circ)=1cos(0∘)=1, tan(0∘)=0\tan(0^\circ)=0tan(0∘)=0
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30°: sin(30∘)=12\sin(30^\circ)=\frac{1}{2}sin(30∘)=21, cos(30∘)=32\cos(30^\circ)=\frac{\sqrt{3}}{2}cos(30∘)=23, tan(30∘)=33\tan(30^\circ)=\frac{\sqrt{3}}{3}tan(30∘)=33
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45°: sin(45∘)=22\sin(45^\circ)=\frac{\sqrt{2}}{2}sin(45∘)=22, cos(45∘)=22\cos(45^\circ)=\frac{\sqrt{2}}{2}cos(45∘)=22, tan(45∘)=1\tan(45^\circ)=1tan(45∘)=1
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60°: sin(60∘)=32\sin(60^\circ)=\frac{\sqrt{3}}{2}sin(60∘)=23, cos(60∘)=12\cos(60^\circ)=\frac{1}{2}cos(60∘)=21, tan(60∘)=3\tan(60^\circ)=\sqrt{3}tan(60∘)=3
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90°: sin(90∘)=1\sin(90^\circ)=1sin(90∘)=1, cos(90∘)=0\cos(90^\circ)=0cos(90∘)=0
Why tan 90° is missing
tan(90∘)\tan(90^\circ)tan(90∘) is not defined because tangent involves dividing by the adjacent side, and at 90° this would mean dividing by zero.
Writing down exact values
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For cos(90∘)\cos(90^\circ)cos(90∘), look at the 90° values: cos(90∘)=0\cos(90^\circ)=0cos(90∘)=0.
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For tan(30∘)\tan(30^\circ)tan(30∘), look at the 30° values: tan(30∘)=33\tan(30^\circ)=\frac{\sqrt{3}}{3}tan(30∘)=33.
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For sin(60∘)\sin(60^\circ)sin(60∘), look at the 60° values: sin(60∘)=32\sin(60^\circ)=\frac{\sqrt{3}}{2}sin(60∘)=23.
Sine pattern
The sine values from 0° to 90° go up as 02\frac{\sqrt{0}}{2}20, 12\frac{\sqrt{1}}{2}21, 22\frac{\sqrt{2}}{2}22, 32\frac{\sqrt{3}}{2}23, 42\frac{\sqrt{4}}{2}24. Cosine uses the same pattern backwards.
Using exact trig values to find lengths
You may also be given a right-angled triangle and asked to calculate a missing side. The method is the same as normal trigonometry, but you substitute an exact value instead of a calculator decimal.
Finding a hypotenuse using 30°
- A right-angled triangle has a 30° angle. The side opposite this angle is 18 cm. Let the hypotenuse be hhh.

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Opposite and hypotenuse means use sine:
sin(30∘)=18h\sin(30^\circ)=\frac{18}{h}sin(30∘)=h18 -
Substitute the exact value sin(30∘)=12\sin(30^\circ)=\frac{1}{2}sin(30∘)=21:
12=18h\frac{1}{2}=\frac{18}{h}21=h18 -
Solve for hhh:
h=36h=36h=36 -
The hypotenuse is 36 cm.
Finding an adjacent side using 60°
- A right-angled triangle has a 60° angle. The side opposite this angle is 18 cm. Let the adjacent side be aaa.

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Opposite and adjacent means use tangent:
tan(60∘)=18a\tan(60^\circ)=\frac{18}{a}tan(60∘)=a18 -
Substitute the exact value tan(60∘)=3\tan(60^\circ)=\sqrt{3}tan(60∘)=3:
3=18a\sqrt{3}=\frac{18}{a}3=a18 -
Rearrange and simplify:
a=183=1833=63a=\frac{18}{\sqrt{3}}=\frac{18\sqrt{3}}{3}=6\sqrt{3}a=318=3183=63 -
The adjacent side is 636\sqrt{3}63 cm.
In the exam
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First identify the angle: is it 0°, 30°, 45°, 60° or 90°?
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If it is a “write down” question, use the memorised exact value directly.
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If it is a triangle question, label opposite, adjacent and hypotenuse before choosing sine, cosine or tangent.
Check yourself
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Can you write down sin(30∘)\sin(30^\circ)sin(30∘), cos(60∘)\cos(60^\circ)cos(60∘) and tan(45∘)\tan(45^\circ)tan(45∘) without a calculator?
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Which exact trig values involve 2\sqrt{2}2?
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In a right-angled triangle, how do you decide which side is opposite?