EFGH EFGH\,EFGH is a trapezium where EF EF\,EF is parallel to HG HG\,HG and ∠EHG=90∘\angle EHG = 90^\circ∠EHG=90∘.
EF=12EF = 12EF=12 mm, HG=20HG = 20HG=20 mm, and FG=14FG = 14FG=14 mm.
Calculate the length of the line EGEGEG.
Give your answer correct to 3 significant figures.
