What you'll learn
- What an equation is and what it means to solve one.
- How to use inverse operations to find an unknown.
- How to solve equations with brackets, fractions, and negative answers.
- How to handle equations with the unknown on both sides.
1. Equations are balanced calculations
An equation is like a set of scales: the left side and the right side have the same value.

Equation, unknown and solution
- An equation is a mathematical statement with an equals sign, such as x+4=11x+4=11x+4=11.
- The unknown is the value you do not know yet, usually shown by a letter like xxx, yyy, or mmm.
- A solution is the value of the unknown that makes the equation true.
Keep the balance
Whatever you do to one side of an equation, you must do to the other side as well.

Finding a missing number
Find the missing number in 14−n=914-n=914−n=9.

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Think: 14 minus what gives 9?
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The difference between 14 and 9 is 5.
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So the missing number is n=5n=5n=5.
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Check: 14 minus 5 gives 9, so it works.
2. One-step equations: adding and subtracting
An inverse operation is the operation that undoes another operation.
Inverse operations
- Adding is undone by subtracting.
- Subtracting is undone by adding.
- Multiplying is undone by dividing.
- Dividing is undone by multiplying.
Example: undoing addition
Solve an equation like x plus a number
Solve x+6=18x+6=18x+6=18.

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The unknown xxx has had 6 added to it.
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Undo adding 6 by subtracting 6 from both sides: x=18−6x=18-6x=18−6.
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So x=12x=12x=12.
Example: undoing subtraction
Solve an equation like x minus a number
Solve p−7=11p-7=11p−7=11.
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The unknown ppp has had 7 subtracted from it.
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Undo subtracting 7 by adding 7 to both sides: p=11+7p=11+7p=11+7.
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So p=18p=18p=18.
Only changing one side
If you subtract 6 from the left side, you must subtract 6 from the right side too. The equals sign means the two sides must stay balanced.
3. One-step equations: multiplying and dividing
When a number is next to a letter, it means multiplication. For example, 7y7y7y means 7 multiplied by yyy.
Coefficient
The coefficient is the number multiplying the unknown. In 7y7y7y, the coefficient is 7.
Multiplication equations
Undo multiplication by dividing
Solve 8a=568a=568a=56.

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8a8a8a means 8 multiplied by aaa.
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Undo multiplying by 8 by dividing both sides by 8.
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a=56÷8a=56\div 8a=56÷8.
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So a=7a=7a=7.
Division equations
Undo division by multiplying
Solve d2=8.5\frac{d}{2}=8.52d=8.5.
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d2\frac{d}{2}2d means ddd divided by 2.
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Undo dividing by 2 by multiplying both sides by 2.
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d=8.5×2d=8.5\times 2d=8.5×2.
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So d=17d=17d=17.
Fraction bar means divide
In equations, a fraction line is another way of showing division. For example, y3\frac{y}{3}3y means yyy divided by 3.
4. Equations can have negative answers
A negative number is a number less than zero, such as -3 or -10.
Sometimes the answer to an equation is negative. This is normal.
Solving when the unknown is being subtracted
Solve 6−m=146-m=146−m=14.

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Since 6 minus something gives a bigger answer, the unknown must be negative.
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Subtract 6 from both sides: −m=8-m=8−m=8.
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If −m=8-m=8−m=8, then m=−8m=-8m=−8.
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Check: 6 minus -8 is 14, so m=−8m=-8m=−8 is correct.
Forgetting the minus sign
If you get −m=8-m=8−m=8, the answer is not m=8m=8m=8. The answer is m=−8m=-8m=−8.
5. Two-step equations
A two-step equation needs two inverse operations to solve it.
Usually, undo adding or subtracting first, then undo multiplying or dividing.
Work backwards
Solve equations by undoing operations in the reverse order to how they were done.
A two-step equation
Solve 3h−5=163h-5=163h−5=16.

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The unknown has been multiplied by 3, then 5 has been subtracted.
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Undo subtracting 5 by adding 5 to both sides: 3h=213h=213h=21.
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Undo multiplying by 3 by dividing both sides by 3.
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So h=7h=7h=7.
A two-step equation with division
Solve y3−4=6\frac{y}{3}-4=63y−4=6.
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Undo subtracting 4 by adding 4 to both sides: y3=10\frac{y}{3}=103y=10.
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Undo dividing by 3 by multiplying both sides by 3.
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So y=30y=30y=30.
6. Equations with brackets
Brackets group parts of an expression together. For example, in 4(x−3)4(x-3)4(x−3), the whole bracket is being multiplied by 4.
You can often solve these by undoing the outside operation first.
A bracket equation
Solve 5(x−4)=355(x-4)=355(x−4)=35.
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The whole bracket is multiplied by 5.
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Undo multiplying by 5 by dividing both sides by 5: x−4=7x-4=7x−4=7.
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Undo subtracting 4 by adding 4 to both sides.
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So x=11x=11x=11.
A bracket with 2x inside
Solve 20=4(2x−1)20=4(2x-1)20=4(2x−1).
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The whole bracket is multiplied by 4, so divide both sides by 4: 5=2x−15=2x-15=2x−1.
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Undo subtracting 1 by adding 1 to both sides: 6=2x6=2x6=2x.
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Undo multiplying by 2 by dividing both sides by 2.
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So x=3x=3x=3.
Divide the whole bracket first
If an equation looks like 4(x−2)=284(x-2)=284(x−2)=28, it is often easiest to divide both sides by 4 before dealing with the inside of the bracket.
7. Fractions with an expression on top
The top of a fraction is called the numerator. The bottom is called the denominator.
If the whole numerator is divided by a number, multiply both sides by that number first.
A fraction equation
Solve d+54=6\frac{d+5}{4}=64d+5=6.
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The whole top, d+5d+5d+5, is divided by 4.
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Undo dividing by 4 by multiplying both sides by 4: d+5=24d+5=24d+5=24.
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Undo adding 5 by subtracting 5 from both sides.
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So d=19d=19d=19.
A fraction with 2x on top
Solve 2x3=8\frac{2x}{3}=832x=8.
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Undo dividing by 3 by multiplying both sides by 3: 2x=242x=242x=24.
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Undo multiplying by 2 by dividing both sides by 2.
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So x=12x=12x=12.
8. Unknowns on both sides
Sometimes the unknown appears on both sides of the equals sign.
A term is a part of an expression, such as 5x5x5x, −2x-2x−2x, or 7. Like terms have the same letter part, such as 6x6x6x and 2x2x2x.
The aim is to collect the unknown terms on one side and the number terms on the other.
Unknown on both sides
Solve 6w+9=3w+246w+9=3w+246w+9=3w+24.

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Subtract 3w3w3w from both sides to get the unknowns on one side: 3w+9=243w+9=243w+9=24.
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Subtract 9 from both sides: 3w=153w=153w=15.
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Divide both sides by 3.
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So w=5w=5w=5.
Try to keep the unknown positive
If possible, move the smaller unknown term to the other side. This can help you avoid negative unknowns.
In the exam
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Write one clear line for each inverse operation you do.
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Do the same operation to both sides every time.
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Substitute your answer back into the original equation to check it works.
Check yourself
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What operation undoes adding 9?
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If −m=12-m=12−m=12, what is mmm?
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When the unknown appears on both sides, which terms should you collect together first?
