A diagram shows a triangle OABOABOAB.
OA→=3a \overrightarrow{OA} = 3\mathbf{a} OA=3a OB→=4b \overrightarrow{OB} = 4\mathbf{b} OB=4bP P\,P is the point on AB AB\,AB such that AP:PB=2:3AP:PB = 2:3AP:PB=2:3
OP→=k(9a+8b) \overrightarrow{OP} = k(9\mathbf{a} + 8\mathbf{b}) OP=k(9a+8b)
Find the value of kkk.
22 exam-style questions on OCR GCSE Maths Vectors Proof Questions. Each one has a worked solution and a mark scheme showing where the marks go.