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Rearranging Harder Formulae

Rearranging Harder Formulae

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Question 29

Verify that making x x\,x the subject of the formula a=4+2bx2x−3\displaystyle a = \frac{4+2bx}{2x-3}a=2x−34+2bx​ gives x=4+3a2a−2b\displaystyle x = \frac{4 + 3a}{2a - 2b}x=2a−2b4+3a​

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Rearranging Harder Formulae Questions

  1. GCSE
  2. /Maths
  3. /Rearranging Harder Formulae

215 exam-style questions on OCR GCSE Maths Rearranging Harder Formulae. Each one has a worked solution and a mark scheme showing where the marks go.

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