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Rearranging Harder Formulae

Rearranging Harder Formulae

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Question 20
a.

Make x x\,x the subject of the formula ab=2xx+5\displaystyle \frac{a}{b} = \frac{2x}{x+5}ba​=x+52x​

[3]
b.

Hence find the value of x x\,x when a=3a=3a=3 and b=4b=4b=4.

[1]
Markscheme

Rearranging Harder Formulae Questions

  1. GCSE
  2. /Maths
  3. /Rearranging Harder Formulae

215 exam-style questions on OCR GCSE Maths Rearranging Harder Formulae. Each one has a worked solution and a mark scheme showing where the marks go.

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