Write x+92x+3\displaystyle \frac{x + 9}{2x + 3}2x+3x+9 in the form x2+7x−182x2−x−6\displaystyle \frac{x^2 + 7x - 18}{2x^2 - x - 6}2x2−x−6x2+7x−18 for x≠2x \ne 2x=2.
255 exam-style questions on OCR GCSE Maths Algebraic Fractions. Each one has a worked solution and a mark scheme showing where the marks go.