Show that (2x+1)(3x−2)2=18x3−15x2−4x+4(2x + 1)(3x - 2)^2 = 18x^3 - 15x^2 - 4x + 4(2x+1)(3x−2)2=18x3−15x2−4x+4 for all values of xxx.
Hence solve the equation
18x3−15x2−4x+4=0 18x^3 - 15x^2 - 4x + 4 = 0 18x3−15x2−4x+4=0225 exam-style questions on OCR GCSE Maths Expanding Triple Brackets. Each one has a worked solution and a mark scheme showing where the marks go.