Show that 12x3−103x2−48x+27=(3x−1)(4x+3)(x−9)12x^3 - 103x^2 - 48x + 27 = (3x - 1)(4x + 3)(x - 9)12x3−103x2−48x+27=(3x−1)(4x+3)(x−9) for all values of xxx.
225 exam-style questions on OCR GCSE Maths Expanding Triple Brackets. Each one has a worked solution and a mark scheme showing where the marks go.