Write down the exact value of θ \theta\,θ when sin(θ)=12\displaystyle \sin(\theta)=\frac{1}{2}sin(θ)=21, given that 0∘<θ<90∘0^\circ<\theta<90^\circ0∘<θ<90∘
219 exam-style questions on OCR GCSE Maths Exact trig values. Each one has a worked solution and a mark scheme showing where the marks go.