32:I[196793,["/_next/static/chunks/2msykuvi-vydm.js?dpl=nogit-1790362613","/_next/static/chunks/2mu6-wo6ccpi3.js?dpl=nogit-1790362613","/_next/static/chunks/2epfhfe5im7r6.js?dpl=nogit-1790362613","/_next/static/chunks/1ew75_i487l-5.js?dpl=nogit-1790362613","/_next/static/chunks/0p4rexedanx97.js?dpl=nogit-1790362613","/_next/static/chunks/0u008gt6051u7.js?dpl=nogit-1790362613","/_next/static/chunks/1odwrcl12kfnl.js?dpl=nogit-1790362613","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1790362613","/_next/static/chunks/3lf9kdvvybemj.js?dpl=nogit-1790362613","/_next/static/chunks/2hyw6fyf3iqeh.js?dpl=nogit-1790362613","/_next/static/chunks/03q735zs9dbpu.js?dpl=nogit-1790362613","/_next/static/chunks/3r5hh4t0jf4es.js?dpl=nogit-1790362613","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1790362613","/_next/static/chunks/1h4wccj42vygd.js?dpl=nogit-1790362613","/_next/static/chunks/12xoy6h_w_le6.js?dpl=nogit-1790362613","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1790362613","/_next/static/chunks/3ht89vb0p09bm.js?dpl=nogit-1790362613","/_next/static/chunks/3ocoqwe4aht_u.js?dpl=nogit-1790362613","/_next/static/chunks/32qmkt01ta8b2.js?dpl=nogit-1790362613","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1790362613","/_next/static/chunks/3ao1re0xmmur_.js?dpl=nogit-1790362613","/_next/static/chunks/3xa2z7fbv2riw.js?dpl=nogit-1790362613","/_next/static/chunks/14kf-an-d2n-e.js?dpl=nogit-1790362613","/_next/static/chunks/381o-754ev9ia.js?dpl=nogit-1790362613","/_next/static/chunks/2tr2cll18vqv3.js?dpl=nogit-1790362613","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1790362613","/_next/static/chunks/3kom3ps_bn2q6.js?dpl=nogit-1790362613","/_next/static/chunks/1x_yxljsdq0vl.js?dpl=nogit-1790362613","/_next/static/chunks/1xkpwfqqdrdio.js?dpl=nogit-1790362613","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1790362613","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1790362613","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1790362613","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1790362613","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1790362613","/_next/static/chunks/440m38krgocdi.js?dpl=nogit-1790362613","/_next/static/chunks/2p6gbbs6zvfpy.js?dpl=nogit-1790362613","/_next/static/chunks/172wsar4r7zzx.js?dpl=nogit-1790362613","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1790362613","/_next/static/chunks/3do_93-6buld5.js?dpl=nogit-1790362613","/_next/static/chunks/1pp_uf_jx5j9r.js?dpl=nogit-1790362613","/_next/static/chunks/1s6j_7_p0ugo9.js?dpl=nogit-1790362613","/_next/static/chunks/2vg15qyptj-oc.js?dpl=nogit-1790362613","/_next/static/chunks/2b6r02yb2zswo.js?dpl=nogit-1790362613","/_next/static/chunks/12mv6p8rwcl5o.js?dpl=nogit-1790362613","/_next/static/chunks/422ba61wql3d7.js?dpl=nogit-1790362613","/_next/static/chunks/0d2u5k628p_lw.js?dpl=nogit-1790362613","/_next/static/chunks/34ux0fo6f-rm8.js?dpl=nogit-1790362613","/_next/static/chunks/3h4suq-9gmzwh.js?dpl=nogit-1790362613","/_next/static/chunks/0rt2_go1it43r.js?dpl=nogit-1790362613","/_next/static/chunks/0v5zhouho0zlq.js?dpl=nogit-1790362613","/_next/static/chunks/1gtlwpzgzi12z.js?dpl=nogit-1790362613","/_next/static/chunks/2zwoemojbdlmi.js?dpl=nogit-1790362613","/_next/static/chunks/2y341-r8ncizo.js?dpl=nogit-1790362613","/_next/static/chunks/3jzaxe43n3e1e.js?dpl=nogit-1790362613","/_next/static/chunks/22z8pa0ys3w4l.js?dpl=nogit-1790362613","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1790362613","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1790362613","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1790362613","/_next/static/chunks/1__39-dgg7p8-.js?dpl=nogit-1790362613","/_next/static/chunks/0pdzmybpnr872.js?dpl=nogit-1790362613","/_next/static/chunks/1zt4k83kx3bkw.js?dpl=nogit-1790362613","/_next/static/chunks/200x0be4hbjpj.js?dpl=nogit-1790362613","/_next/static/chunks/35bn8r0ao86_s.js?dpl=nogit-1790362613","/_next/static/chunks/3wqp-h5xnebw9.js?dpl=nogit-1790362613","/_next/static/chunks/120-bka6zq5lp.js?dpl=nogit-1790362613","/_next/static/chunks/30dopbgd1dkf9.js?dpl=nogit-1790362613","/_next/static/chunks/43ajf4ofaeu5y.js?dpl=nogit-1790362613"],"Gingerbread"] 34:I[647935,["/_next/static/chunks/2msykuvi-vydm.js?dpl=nogit-1790362613","/_next/static/chunks/2mu6-wo6ccpi3.js?dpl=nogit-1790362613","/_next/static/chunks/2epfhfe5im7r6.js?dpl=nogit-1790362613","/_next/static/chunks/1ew75_i487l-5.js?dpl=nogit-1790362613","/_next/static/chunks/0p4rexedanx97.js?dpl=nogit-1790362613","/_next/static/chunks/0u008gt6051u7.js?dpl=nogit-1790362613","/_next/static/chunks/1odwrcl12kfnl.js?dpl=nogit-1790362613","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1790362613","/_next/static/chunks/3lf9kdvvybemj.js?dpl=nogit-1790362613","/_next/static/chunks/2hyw6fyf3iqeh.js?dpl=nogit-1790362613","/_next/static/chunks/03q735zs9dbpu.js?dpl=nogit-1790362613","/_next/static/chunks/3r5hh4t0jf4es.js?dpl=nogit-1790362613","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1790362613","/_next/static/chunks/1h4wccj42vygd.js?dpl=nogit-1790362613","/_next/static/chunks/12xoy6h_w_le6.js?dpl=nogit-1790362613","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1790362613","/_next/static/chunks/3ht89vb0p09bm.js?dpl=nogit-1790362613","/_next/static/chunks/3ocoqwe4aht_u.js?dpl=nogit-1790362613","/_next/static/chunks/32qmkt01ta8b2.js?dpl=nogit-1790362613","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1790362613","/_next/static/chunks/3ao1re0xmmur_.js?dpl=nogit-1790362613","/_next/static/chunks/3xa2z7fbv2riw.js?dpl=nogit-1790362613","/_next/static/chunks/14kf-an-d2n-e.js?dpl=nogit-1790362613","/_next/static/chunks/381o-754ev9ia.js?dpl=nogit-1790362613","/_next/static/chunks/2tr2cll18vqv3.js?dpl=nogit-1790362613","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1790362613","/_next/static/chunks/3kom3ps_bn2q6.js?dpl=nogit-1790362613","/_next/static/chunks/1x_yxljsdq0vl.js?dpl=nogit-1790362613","/_next/static/chunks/1xkpwfqqdrdio.js?dpl=nogit-1790362613","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1790362613","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1790362613","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1790362613","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1790362613","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1790362613","/_next/static/chunks/440m38krgocdi.js?dpl=nogit-1790362613","/_next/static/chunks/2p6gbbs6zvfpy.js?dpl=nogit-1790362613","/_next/static/chunks/172wsar4r7zzx.js?dpl=nogit-1790362613","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1790362613","/_next/static/chunks/3do_93-6buld5.js?dpl=nogit-1790362613","/_next/static/chunks/1pp_uf_jx5j9r.js?dpl=nogit-1790362613","/_next/static/chunks/1s6j_7_p0ugo9.js?dpl=nogit-1790362613","/_next/static/chunks/2vg15qyptj-oc.js?dpl=nogit-1790362613","/_next/static/chunks/2b6r02yb2zswo.js?dpl=nogit-1790362613","/_next/static/chunks/12mv6p8rwcl5o.js?dpl=nogit-1790362613","/_next/static/chunks/422ba61wql3d7.js?dpl=nogit-1790362613","/_next/static/chunks/0d2u5k628p_lw.js?dpl=nogit-1790362613","/_next/static/chunks/34ux0fo6f-rm8.js?dpl=nogit-1790362613","/_next/static/chunks/3h4suq-9gmzwh.js?dpl=nogit-1790362613","/_next/static/chunks/0rt2_go1it43r.js?dpl=nogit-1790362613","/_next/static/chunks/0v5zhouho0zlq.js?dpl=nogit-1790362613","/_next/static/chunks/1gtlwpzgzi12z.js?dpl=nogit-1790362613","/_next/static/chunks/2zwoemojbdlmi.js?dpl=nogit-1790362613","/_next/static/chunks/2y341-r8ncizo.js?dpl=nogit-1790362613","/_next/static/chunks/3jzaxe43n3e1e.js?dpl=nogit-1790362613","/_next/static/chunks/22z8pa0ys3w4l.js?dpl=nogit-1790362613","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1790362613","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1790362613","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1790362613","/_next/static/chunks/1__39-dgg7p8-.js?dpl=nogit-1790362613","/_next/static/chunks/0pdzmybpnr872.js?dpl=nogit-1790362613","/_next/static/chunks/1zt4k83kx3bkw.js?dpl=nogit-1790362613","/_next/static/chunks/200x0be4hbjpj.js?dpl=nogit-1790362613","/_next/static/chunks/35bn8r0ao86_s.js?dpl=nogit-1790362613","/_next/static/chunks/3wqp-h5xnebw9.js?dpl=nogit-1790362613","/_next/static/chunks/120-bka6zq5lp.js?dpl=nogit-1790362613","/_next/static/chunks/30dopbgd1dkf9.js?dpl=nogit-1790362613","/_next/static/chunks/43ajf4ofaeu5y.js?dpl=nogit-1790362613"],"RecordResourceResume"] 35:I[830476,["/_next/static/chunks/2msykuvi-vydm.js?dpl=nogit-1790362613","/_next/static/chunks/2mu6-wo6ccpi3.js?dpl=nogit-1790362613","/_next/static/chunks/2epfhfe5im7r6.js?dpl=nogit-1790362613","/_next/static/chunks/1ew75_i487l-5.js?dpl=nogit-1790362613","/_next/static/chunks/0p4rexedanx97.js?dpl=nogit-1790362613","/_next/static/chunks/0u008gt6051u7.js?dpl=nogit-1790362613","/_next/static/chunks/1odwrcl12kfnl.js?dpl=nogit-1790362613","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1790362613","/_next/static/chunks/3lf9kdvvybemj.js?dpl=nogit-1790362613","/_next/static/chunks/2hyw6fyf3iqeh.js?dpl=nogit-1790362613","/_next/static/chunks/03q735zs9dbpu.js?dpl=nogit-1790362613","/_next/static/chunks/3r5hh4t0jf4es.js?dpl=nogit-1790362613","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1790362613","/_next/static/chunks/1h4wccj42vygd.js?dpl=nogit-1790362613","/_next/static/chunks/12xoy6h_w_le6.js?dpl=nogit-1790362613","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1790362613","/_next/static/chunks/3ht89vb0p09bm.js?dpl=nogit-1790362613","/_next/static/chunks/3ocoqwe4aht_u.js?dpl=nogit-1790362613","/_next/static/chunks/32qmkt01ta8b2.js?dpl=nogit-1790362613","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1790362613","/_next/static/chunks/3ao1re0xmmur_.js?dpl=nogit-1790362613","/_next/static/chunks/3xa2z7fbv2riw.js?dpl=nogit-1790362613","/_next/static/chunks/14kf-an-d2n-e.js?dpl=nogit-1790362613","/_next/static/chunks/381o-754ev9ia.js?dpl=nogit-1790362613","/_next/static/chunks/2tr2cll18vqv3.js?dpl=nogit-1790362613","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1790362613","/_next/static/chunks/3kom3ps_bn2q6.js?dpl=nogit-1790362613","/_next/static/chunks/1x_yxljsdq0vl.js?dpl=nogit-1790362613","/_next/static/chunks/1xkpwfqqdrdio.js?dpl=nogit-1790362613","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1790362613","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1790362613","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1790362613","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1790362613","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1790362613","/_next/static/chunks/440m38krgocdi.js?dpl=nogit-1790362613","/_next/static/chunks/2p6gbbs6zvfpy.js?dpl=nogit-1790362613","/_next/static/chunks/172wsar4r7zzx.js?dpl=nogit-1790362613","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1790362613","/_next/static/chunks/3do_93-6buld5.js?dpl=nogit-1790362613","/_next/static/chunks/1pp_uf_jx5j9r.js?dpl=nogit-1790362613","/_next/static/chunks/1s6j_7_p0ugo9.js?dpl=nogit-1790362613","/_next/static/chunks/2vg15qyptj-oc.js?dpl=nogit-1790362613","/_next/static/chunks/2b6r02yb2zswo.js?dpl=nogit-1790362613","/_next/static/chunks/12mv6p8rwcl5o.js?dpl=nogit-1790362613","/_next/static/chunks/422ba61wql3d7.js?dpl=nogit-1790362613","/_next/static/chunks/0d2u5k628p_lw.js?dpl=nogit-1790362613","/_next/static/chunks/34ux0fo6f-rm8.js?dpl=nogit-1790362613","/_next/static/chunks/3h4suq-9gmzwh.js?dpl=nogit-1790362613","/_next/static/chunks/0rt2_go1it43r.js?dpl=nogit-1790362613","/_next/static/chunks/0v5zhouho0zlq.js?dpl=nogit-1790362613","/_next/static/chunks/1gtlwpzgzi12z.js?dpl=nogit-1790362613","/_next/static/chunks/2zwoemojbdlmi.js?dpl=nogit-1790362613","/_next/static/chunks/2y341-r8ncizo.js?dpl=nogit-1790362613","/_next/static/chunks/3jzaxe43n3e1e.js?dpl=nogit-1790362613","/_next/static/chunks/22z8pa0ys3w4l.js?dpl=nogit-1790362613","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1790362613","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1790362613","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1790362613","/_next/static/chunks/1__39-dgg7p8-.js?dpl=nogit-1790362613","/_next/static/chunks/0pdzmybpnr872.js?dpl=nogit-1790362613","/_next/static/chunks/1zt4k83kx3bkw.js?dpl=nogit-1790362613","/_next/static/chunks/200x0be4hbjpj.js?dpl=nogit-1790362613","/_next/static/chunks/35bn8r0ao86_s.js?dpl=nogit-1790362613","/_next/static/chunks/3wqp-h5xnebw9.js?dpl=nogit-1790362613","/_next/static/chunks/120-bka6zq5lp.js?dpl=nogit-1790362613","/_next/static/chunks/30dopbgd1dkf9.js?dpl=nogit-1790362613","/_next/static/chunks/43ajf4ofaeu5y.js?dpl=nogit-1790362613"],"FlashcardAccessBranch"] 36:I[315438,["/_next/static/chunks/2msykuvi-vydm.js?dpl=nogit-1790362613","/_next/static/chunks/2mu6-wo6ccpi3.js?dpl=nogit-1790362613","/_next/static/chunks/2epfhfe5im7r6.js?dpl=nogit-1790362613","/_next/static/chunks/1ew75_i487l-5.js?dpl=nogit-1790362613","/_next/static/chunks/0p4rexedanx97.js?dpl=nogit-1790362613","/_next/static/chunks/0u008gt6051u7.js?dpl=nogit-1790362613","/_next/static/chunks/1odwrcl12kfnl.js?dpl=nogit-1790362613","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1790362613","/_next/static/chunks/3lf9kdvvybemj.js?dpl=nogit-1790362613","/_next/static/chunks/2hyw6fyf3iqeh.js?dpl=nogit-1790362613","/_next/static/chunks/03q735zs9dbpu.js?dpl=nogit-1790362613","/_next/static/chunks/3r5hh4t0jf4es.js?dpl=nogit-1790362613","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1790362613","/_next/static/chunks/1h4wccj42vygd.js?dpl=nogit-1790362613","/_next/static/chunks/12xoy6h_w_le6.js?dpl=nogit-1790362613","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1790362613","/_next/static/chunks/3ht89vb0p09bm.js?dpl=nogit-1790362613","/_next/static/chunks/3ocoqwe4aht_u.js?dpl=nogit-1790362613","/_next/static/chunks/32qmkt01ta8b2.js?dpl=nogit-1790362613","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1790362613","/_next/static/chunks/3ao1re0xmmur_.js?dpl=nogit-1790362613","/_next/static/chunks/3xa2z7fbv2riw.js?dpl=nogit-1790362613","/_next/static/chunks/14kf-an-d2n-e.js?dpl=nogit-1790362613","/_next/static/chunks/381o-754ev9ia.js?dpl=nogit-1790362613","/_next/static/chunks/2tr2cll18vqv3.js?dpl=nogit-1790362613","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1790362613","/_next/static/chunks/3kom3ps_bn2q6.js?dpl=nogit-1790362613","/_next/static/chunks/1x_yxljsdq0vl.js?dpl=nogit-1790362613","/_next/static/chunks/1xkpwfqqdrdio.js?dpl=nogit-1790362613","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1790362613","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1790362613","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1790362613","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1790362613","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1790362613","/_next/static/chunks/440m38krgocdi.js?dpl=nogit-1790362613","/_next/static/chunks/2p6gbbs6zvfpy.js?dpl=nogit-1790362613","/_next/static/chunks/172wsar4r7zzx.js?dpl=nogit-1790362613","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1790362613","/_next/static/chunks/3do_93-6buld5.js?dpl=nogit-1790362613","/_next/static/chunks/1pp_uf_jx5j9r.js?dpl=nogit-1790362613","/_next/static/chunks/1s6j_7_p0ugo9.js?dpl=nogit-1790362613","/_next/static/chunks/2vg15qyptj-oc.js?dpl=nogit-1790362613","/_next/static/chunks/2b6r02yb2zswo.js?dpl=nogit-1790362613","/_next/static/chunks/12mv6p8rwcl5o.js?dpl=nogit-1790362613","/_next/static/chunks/422ba61wql3d7.js?dpl=nogit-1790362613","/_next/static/chunks/0d2u5k628p_lw.js?dpl=nogit-1790362613","/_next/static/chunks/34ux0fo6f-rm8.js?dpl=nogit-1790362613","/_next/static/chunks/3h4suq-9gmzwh.js?dpl=nogit-1790362613","/_next/static/chunks/0rt2_go1it43r.js?dpl=nogit-1790362613","/_next/static/chunks/0v5zhouho0zlq.js?dpl=nogit-1790362613","/_next/static/chunks/1gtlwpzgzi12z.js?dpl=nogit-1790362613","/_next/static/chunks/2zwoemojbdlmi.js?dpl=nogit-1790362613","/_next/static/chunks/2y341-r8ncizo.js?dpl=nogit-1790362613","/_next/static/chunks/3jzaxe43n3e1e.js?dpl=nogit-1790362613","/_next/static/chunks/22z8pa0ys3w4l.js?dpl=nogit-1790362613","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1790362613","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1790362613","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1790362613","/_next/static/chunks/1__39-dgg7p8-.js?dpl=nogit-1790362613","/_next/static/chunks/0pdzmybpnr872.js?dpl=nogit-1790362613","/_next/static/chunks/1zt4k83kx3bkw.js?dpl=nogit-1790362613","/_next/static/chunks/200x0be4hbjpj.js?dpl=nogit-1790362613","/_next/static/chunks/35bn8r0ao86_s.js?dpl=nogit-1790362613","/_next/static/chunks/3wqp-h5xnebw9.js?dpl=nogit-1790362613","/_next/static/chunks/120-bka6zq5lp.js?dpl=nogit-1790362613","/_next/static/chunks/30dopbgd1dkf9.js?dpl=nogit-1790362613","/_next/static/chunks/43ajf4ofaeu5y.js?dpl=nogit-1790362613"],"TopicFlashcardRunner"] 23:[["$","$L32",null,{"feature":"flashcards"}],"$L33",["$","$L34",null,{"href":"/gcse/maths/ocr/grade-2-2-14-averages/flashcards","label":"Averages","subjectCode":"gcse_maths__ocr","surface":"flashcards"}],["$","$L35",null,{"runner":["$","div",null,{"className":"min-h-0 flex-1 overflow-hidden bg-background","children":["$","$L36",null,{"decks":[{"id":"22478c1e-91e9-72fe-834b-9de7b4cfb5c9","title":"Averages Flashcards","topicId":"09a94373-b65b-4c47-a8de-34ce8ec2946d","topicSlug":"grade-2-2-14-averages","cards":[{"id":"c75692ac-3ee9-4b15-fdf4-15e218adf6f1","cardType":"cloze","points":null,"front":"The [ ] is the middle value after the data are in [ ].","back":"The median is the middle value after the data are in order.","mcqOptions":[{"text":"The median is the middle value after the data are in order.","correct":true,"explanation":"The median is found by arranging the data in order and identifying the middle value, or the two middle values when the data set has even size."},{"text":"The mean is the middle value after the data are in order.","correct":false,"explanation":"This confuses the median with the mean. The median is the middle value after the data have been placed in order."},{"text":"The median is the middle value after the data are in groups.","correct":false,"explanation":"Grouping the data does not reliably reveal its middle value. The median is found after the values have been arranged in order."},{"text":"The mode is the middle value after the data are in frequency order.","correct":false,"explanation":"This mixes up the mode and median. The mode is based on frequency, while the median is the middle value after ordering the data."}]},{"id":"e20fea0d-a4f2-8e71-d286-3ebd80d70bdb","cardType":"basic","points":2,"front":"Why is the middle of the original list unsafe for the median?","back":"The list may not be in order.","mcqOptions":[{"text":"The list may not be in order.","correct":true,"explanation":"Position alone is meaningful only after sorting. In an unordered original list, the central written entry may not be the median value."},{"text":"The list may contain repeated values.","correct":false,"explanation":"Repeated values do not make the median unsafe. The problem is that the original list may not be in order, so its written middle can be misleading."},{"text":"The list may have an odd length.","correct":false,"explanation":"An odd number of values actually gives one middle position after sorting. The original list is unsafe because it may not be in order."},{"text":"The list may include negative values.","correct":false,"explanation":"Negative values can be ordered and included normally when finding a median. The danger is using the middle position before putting the list in order."}]},{"id":"dd882ac2-04c8-fcbe-ddcc-3e7447ecd64c","cardType":"cloze","points":null,"front":"The [ ] is the value that appears [ ].","back":"The mode is the value that appears most often.","mcqOptions":[{"text":"The mode is the value that appears most often.","correct":true,"explanation":"The mode is determined by frequency: it is the value occurring most often in the data set, not a measure based on position or calculation."},{"text":"The median is the value that appears most often.","correct":false,"explanation":"This confuses the median with the mode. The median concerns the middle position, whereas the mode is the value that appears most often."},{"text":"The mode is the value that appears least often.","correct":false,"explanation":"The least frequent value is not the mode. The mode is the value with the greatest frequency, meaning it appears most often."},{"text":"The mean is the value that appears least often.","correct":false,"explanation":"The mean is calculated by dividing the total by the number of values, not by counting the least frequent value. The mode appears most often."}]},{"id":"8f3a7d98-1014-a019-61c6-20eefb5e7029","cardType":"basic","points":1,"front":"What is the mode of 5, 8, 8, 9, 10, 8, 11?","back":"8","mcqOptions":[{"text":"8","correct":true,"explanation":"The value 8 occurs three times, while every other value occurs once. It therefore has the greatest frequency and is the mode."},{"text":"9","correct":false,"explanation":"Choosing 9 may come from inspecting the centre of the written list rather than counting frequencies. The value 8 appears three times, so the mode is 8."},{"text":"11","correct":false,"explanation":"Choosing 11 confuses the mode with the maximum value. The mode is determined by frequency, and 8 occurs three times, more than any other value."},{"text":"5","correct":false,"explanation":"Choosing 5 confuses the mode with the minimum value. The value occurring most often is 8, which appears three times in the list."}]},{"id":"7c5f7e93-3046-599d-ab31-9d48ac818d33","cardType":"basic","points":1,"front":"If no value repeats, what is the mode?","back":"There is no mode.","mcqOptions":[{"text":"There is no mode.","correct":true,"explanation":"A mode must have a greater frequency than the other values. If every value occurs only once, no value is most frequent, so there is no mode."},{"text":"There is a mode.","correct":false,"explanation":"Equal frequencies do not make every value a mode in this GCSE context. If no value repeats, none occurs most often, so there is no mode."},{"text":"The first value is the mode.","correct":false,"explanation":"The first value's position does not make it the mode. The mode depends on frequency, and with no repeated values there is no mode."},{"text":"The largest value is the mode.","correct":false,"explanation":"The largest value is the maximum, not automatically the mode. Since no value repeats, none has the greatest frequency and there is no mode."}]},{"id":"b7d4a069-eef5-88bd-d4f3-b7b05c69f489","cardType":"cloze","points":null,"front":"The range is [ ] minus [ ].","back":"The range is largest value minus smallest value.","mcqOptions":[{"text":"The range is largest value minus smallest value.","correct":true,"explanation":"The range measures the total spread of the data, so it is calculated by subtracting the smallest value from the largest value."},{"text":"The range is smallest value minus largest value.","correct":false,"explanation":"Reversing the subtraction usually produces a negative result. The range is non-negative and is found using largest value minus smallest value."},{"text":"The range is largest value minus second smallest value.","correct":false,"explanation":"Using the second smallest value ignores part of the data's spread. The range must use both extremes: largest value minus smallest value."},{"text":"The range is highest frequency minus smallest value.","correct":false,"explanation":"Frequency determines the mode, not the range. To measure the spread, subtract the smallest value in the data set from the largest value."}]},{"id":"b0c0027c-e945-d4ab-af3c-713c0d926378","cardType":"basic","points":2,"front":"What is the range of 152 cm, 168 cm, 160 cm, 174 cm, 152 cm, 181 cm?","back":"29 cm","mcqOptions":[{"text":"29 cm","correct":true,"explanation":"The largest measurement is 181 cm and the smallest is 152 cm. Subtracting them gives a range of $181-152=29$ cm."},{"text":"28 cm","correct":false,"explanation":"This off-by-one result can come from counting whole centimetres between the endpoints. The range uses direct subtraction: $181-152=29$ cm."},{"text":"21 cm","correct":false,"explanation":"This uses 160 cm as the minimum and overlooks the two 152 cm values. The correct extremes give $181-152=29$ cm."},{"text":"333 cm","correct":false,"explanation":"This adds the largest and smallest measurements instead of subtracting them. The range is the difference, so $181-152=29$ cm."}]},{"id":"bf6e31a3-6a04-ef3f-e48c-c067bf7a3cb5","cardType":"cloze","points":null,"front":"With an [ ] number of values, the median uses the [ ].","back":"With an even number of values, the median uses the two middle values.","mcqOptions":[{"text":"With an even number of values, the median uses the two middle values.","correct":true,"explanation":"An even-sized ordered data set has no single central position. Its median is therefore found from the two middle values, usually by calculating their mean."},{"text":"With an odd number of values, the median uses the two middle values.","correct":false,"explanation":"An odd number of values has one middle value after ordering, not two. The median uses two middle values when the number of values is even."},{"text":"With an even number of values, the median uses the middle value.","correct":false,"explanation":"An even-sized data set has two central positions, so choosing only one would be arbitrary. The median must use the two middle values."},{"text":"With an odd number of values, the median uses the middle value.","correct":false,"explanation":"This states the rule for an odd-sized data set. When the number of values is even, the median uses the two middle values instead."}]},{"id":"b96dba3e-d16e-95ed-e6d0-87c8d20038cc","cardType":"basic","points":2,"front":"What is the median of 118 g, 124 g, 126 g, 132 g, 140 g, 150 g?","back":"129 g","mcqOptions":[{"text":"129 g","correct":true,"explanation":"With six ordered values, the median is the mean of the two middle values. The middle values are 126 g and 132 g, giving $(126+132)\\div2=129$ g."},{"text":"126 g","correct":false,"explanation":"This selects the lower middle value instead of averaging both middle values. For six values, average 126 g and 132 g to obtain the median of 129 g."},{"text":"132 g","correct":false,"explanation":"This selects the upper middle value instead of averaging both middle values. Because there are six values, the median is $(126+132)\\div2=129$ g."},{"text":"131 g","correct":false,"explanation":"This results from averaging the wrong pair of values. The two middle values are 126 g and 132 g, whose mean is 129 g."}]},{"id":"13bfbba8-11d3-ce76-0283-b79df9dd212f","cardType":"cloze","points":null,"front":"For the mean, divide the [ ] by the [ ].","back":"For the mean, divide the total of values by the number of values.","mcqOptions":[{"text":"For the mean, divide the total of values by the number of values.","correct":true,"explanation":"The mean is calculated by adding all the values to find their total, then dividing that total by how many values there are."},{"text":"For the mean, divide the number of values by the total of values.","correct":false,"explanation":"This reverses the mean calculation. The total of the values must be divided by the number of values, not the number divided by the total."},{"text":"For the mean, divide the total of values by the range of values.","correct":false,"explanation":"The range measures spread and is not the divisor when finding a mean. Divide the total of the values by the number of values."},{"text":"For the mean, divide the highest value by the number of values.","correct":false,"explanation":"Using only the highest value ignores the other data values. The mean requires the total of all values to be divided by the number of values."}]},{"id":"62bdec1d-cf42-2109-f750-d209a583f18f","cardType":"basic","points":2,"front":"What is the mean of 14, 6, 10, 6, 12, 18?","back":"11","mcqOptions":[{"text":"11","correct":true,"explanation":"The six values total $14+6+10+6+12+18=66$. Dividing this total by 6 gives a mean of $66\\div6=11$."},{"text":"10","correct":false,"explanation":"This is the median, found from the middle pair after ordering, rather than the mean. The total is 66, so the mean is $66\\div6=11$."},{"text":"12","correct":false,"explanation":"This can result from an addition or division slip. The values total 66, and dividing by all six values gives $66\\div6=11$, not 12."},{"text":"66","correct":false,"explanation":"This is the total of the values rather than their mean. The total of 66 must be divided by the six values, giving a mean of 11."}]},{"id":"20e62e5a-95f0-47bf-1447-6d31c1937c0d","cardType":"cloze","points":null,"front":"To work backwards from a mean: [ ] = [ ].","back":"To work backwards from a mean: total = mean × number of values.","mcqOptions":[{"text":"To work backwards from a mean: total = mean × number of values.","correct":true,"explanation":"Since mean equals total divided by the number of values, reversing the division gives total equals mean multiplied by the number of values."},{"text":"To work backwards from a mean: mean = total × number of values.","correct":false,"explanation":"This incorrectly multiplies the total by the number of values. To reconstruct the total, multiply the mean by the number of values."},{"text":"To work backwards from a mean: total = mean ÷ number of values.","correct":false,"explanation":"Dividing the mean by the number of values makes the result too small. The total is found by multiplying the mean by the number of values."},{"text":"To work backwards from a mean: number of values = total × mean.","correct":false,"explanation":"This uses multiplication while making the number of values the subject incorrectly. The required relationship is total equals mean multiplied by number of values."}]},{"id":"9117a55a-c181-b688-94c3-1630b1f29fd2","cardType":"basic","points":1,"front":"If 6 numbers have mean 10, what total must they have?","back":"60","mcqOptions":[{"text":"60","correct":true,"explanation":"The total is found by multiplying the mean by the number of values. Therefore, the required total is $10\\times6=60$."},{"text":"16","correct":false,"explanation":"This adds the mean and number of values instead of multiplying them. A mean of 10 across 6 numbers requires a total of $10\\times6=60$."},{"text":"50","correct":false,"explanation":"This effectively accounts for only five values at the stated mean. All six numbers must total $6\\times10=60$, not 50."},{"text":"70","correct":false,"explanation":"This effectively includes one extra value at the stated mean. For six numbers, multiply $6\\times10$ to obtain the required total of 60."}]},{"id":"f5376082-b091-9a06-8311-7d106fa7aad8","cardType":"basic","points":1,"front":"Seven values have mean 9. What total is needed?","back":"63","mcqOptions":[{"text":"63","correct":true,"explanation":"The total equals the mean multiplied by the number of values. With seven values of mean 9, the required total is $7\\times9=63$."},{"text":"16","correct":false,"explanation":"This adds 7 and 9 rather than multiplying them. The total needed for seven values with mean 9 is $7\\times9=63$."},{"text":"56","correct":false,"explanation":"This uses 8 as the number of values, producing $8\\times7=56$. There are seven values with mean 9, so the total is 63."},{"text":"72","correct":false,"explanation":"This treats the data as if there were eight values of mean 9. There are only seven, so the required total is $7\\times9=63$."}]},{"id":"8598290e-6a3e-e401-05c8-bd13a9691eff","cardType":"basic","points":2,"front":"12, 5, 9, 10, 8, 11, ? have mean 9. What is ?","back":"8","mcqOptions":[{"text":"8","correct":true,"explanation":"Seven values with mean 9 must total $7\\times9=63$. The six known values total 55, so the missing value is $63-55=8$."},{"text":"7","correct":false,"explanation":"This may come from misadding the known values as 56. Their actual total is 55, so the missing value is $63-55=8$."},{"text":"9","correct":false,"explanation":"This assumes the missing value must equal the mean. The known values total 55, so 8 is needed to reach the required total of 63."},{"text":"18","correct":false,"explanation":"This confuses the required adjustment with a much larger value. The target total is 63 and the known total is 55, leaving only 8."}]},{"id":"272c08c2-773a-1115-9681-c0bc562ed6ec","cardType":"basic","points":2,"front":"2, 4, ?, 7, 5, ? have mean 5. What must the hidden numbers add to?","back":"12","mcqOptions":[{"text":"12","correct":true,"explanation":"Six values with mean 5 need a total of $6\\times5=30$. The known values total 18, so the hidden numbers must add to $30-18=12$."},{"text":"30","correct":false,"explanation":"This is the required total of all six values, not the sum of the hidden numbers. Subtracting the known total of 18 leaves 12."},{"text":"18","correct":false,"explanation":"This is the sum of the four visible numbers rather than the hidden numbers. The full total must be 30, so the hidden sum is $30-18=12$."},{"text":"10","correct":false,"explanation":"This assumes both hidden numbers must individually equal the mean. They only need to balance the data, and their combined total must be $30-18=12$."}]},{"id":"1f4925e4-2064-3d55-18b9-318a77ec608d","cardType":"basic","points":1,"front":"For 2, 4, ?, 7, 5, ? with mode 4, what must one hidden number be?","back":"4","mcqOptions":[{"text":"4","correct":true,"explanation":"The list currently contains only one 4, so at least one hidden number must also be 4 for 4 to occur most often and be the mode."},{"text":"2","correct":false,"explanation":"Choosing 2 would only repeat the 2 and could make it the mode instead. At least one hidden number must be 4 so that 4 occurs most often."},{"text":"5","correct":false,"explanation":"Choosing 5 would repeat the 5 rather than ensure that 4 is the mode. One of the hidden numbers must be 4 to increase its frequency."},{"text":"7","correct":false,"explanation":"Choosing 7 would repeat the 7, so it would not ensure that 4 becomes the mode. At least one hidden number must be 4."}]},{"id":"fefb5aaa-1af5-9666-20c2-793caf0480b7","cardType":"basic","points":1,"front":"If two hidden numbers add to 12 and one is 4, what is the other?","back":"8","mcqOptions":[{"text":"8","correct":true,"explanation":"The hidden numbers have a total of 12, so subtract the known number: $12-4=8$. Therefore, the other hidden number is 8."},{"text":"6","correct":false,"explanation":"Halving 12 assumes that the two hidden numbers are equal, but one is already known to be 4. Subtracting gives $12-4=8$."},{"text":"16","correct":false,"explanation":"Adding 12 and 4 finds a total larger than the stated combined value. The other number is found by subtraction: $12-4=8$."},{"text":"3","correct":false,"explanation":"Dividing 12 by 4 confuses the known number with a number of equal groups. Since the two numbers total 12, the other is $12-4=8$."}]},{"id":"643d9e48-fd40-2642-1dec-e70fc8efade3","cardType":"basic","points":1,"front":"When adding a new value, what should you do to the old mean first?","back":"Turn it back into a total.","mcqOptions":[{"text":"Turn it back into a total.","correct":true,"explanation":"A mean does not preserve the full sum by itself. Multiply the old mean by the old number of values to recover the total before adding the new value."},{"text":"Turn it back into a median.","correct":false,"explanation":"The median is the middle ordered value and cannot be recovered from the mean alone. Instead, multiply the old mean by the number of values to obtain the total."},{"text":"Turn it back into a range.","correct":false,"explanation":"The range is the difference between the greatest and least values, not a step in updating a mean. First convert the old mean into a total."},{"text":"Turn it back into a frequency.","correct":false,"explanation":"A frequency records how often a value occurs, so it cannot be obtained by converting the mean. Multiply the old mean by the number of values to recover the total."}]},{"id":"3f459901-b1bb-8f49-232b-6857b067981c","cardType":"basic","points":3,"front":"Mean of 6 numbers is 20. Mean of 2 is 14. What is the mean of the other 4?","back":"23","mcqOptions":[{"text":"23","correct":true,"explanation":"The total of all six numbers is $6\\times20=120$, while the two numbers total $2\\times14=28$. The remaining mean is $(120-28)\\div4=23$."},{"text":"26","correct":false,"explanation":"This treats the two subgroup means as equally weighted and solves $(14+x)\\div2=20$. The groups have different sizes; using their totals gives $(120-28)\\div4=23$."},{"text":"26.5","correct":false,"explanation":"This subtracts the subgroup mean 14 only once from the total, giving $(120-14)\\div4=26.5$. Its two values actually total 28, so the answer is 23."},{"text":"22","correct":false,"explanation":"This results from the subtraction error $120-28=88$. The correct remaining total is 92, and dividing it by the four remaining numbers gives 23."}]}]}],"examCountdown":{"examDate":"2027-05-14","paperLabel":"Paper 1"},"heading":"Averages","title":"Averages Flashcards","topbar":{"backHref":"/gcse/maths/ocr/flashcards"},"topicSidebar":"$L37"}]}],"topicId":"09a94373-b65b-4c47-a8de-34ce8ec2946d","walled":"$L38"}],"$L39","$L3a"]