The function h h\,h is defined such that
h(x)=x2−16 h(x) = x^2 - 16 h(x)=x2−16Find an expression for h(x+1)h(x + 1)h(x+1)
Hence solve: h(x+1)=0h(x + 1) = 0h(x+1)=0
136 exam-style questions on Eduqas GCSE Maths Inverse and Composite Functions. Each one has a worked solution and a mark scheme showing where the marks go.