Show that 3x+6x−4÷2x2+9x+10x2−4x=3x2x+5\displaystyle \frac{3x+6}{x-4} \div \frac{2x^2+9x+10}{x^2-4x} = \frac{3x}{2x+5}x−43x+6÷x2−4x2x2+9x+10=2x+53x
255 exam-style questions on Eduqas GCSE Maths Algebraic Fractions. Each one has a worked solution and a mark scheme showing where the marks go.