Solve 7x+1−43x−2=1\displaystyle \frac{7}{x + 1} - \frac{4}{3x - 2} = 1x+17−3x−24=1. Hence find the value of 1x1+1x2\displaystyle \frac{1}{x_1}+\frac{1}{x_2}x11+x21, where x1 x_1\,x1 and x2 x_2\,x2 are the two solutions.
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