Solve 24−x+3x+8=1\displaystyle \frac{2}{4 - x} + \frac{3}{x + 8} = 14−x2+x+83=1. Hence find the value of 1x1+1x2\displaystyle \frac{1}{x_1}+\frac{1}{x_2}x11+x21, where x1 x_1\,x1 and x2 x_2\,x2 are the two solutions.
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