Solve x2+4x−1=0x^2 + 4x - 1 = 0x2+4x−1=0
Give your answers in the form a±bca \pm b\sqrt{c}a±bc.
Hence solve (x−3)2+4(x−3)−1=0(x-3)^2 + 4(x-3) - 1 = 0(x−3)2+4(x−3)−1=0.
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